You'll need to add 2 3/7 to <span> 3 4/7 to make 6.
3 + 2 = 5 4/7 + 3/7 = 7/7 =1
5+1=6</span>
Answer:
![\sqrt[5]{2^4}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%5E4%7D)
Step-by-step explanation:
Maybe you want 2^(4/5) in radical form.
The denominator of the fractional power is the index of the root. Either the inside or the outside can be raised to the power of the numerator.
![2^{\frac{4}{5}}=\boxed{\sqrt[5]{2^4}=(\sqrt[5]{2})^4}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B4%7D%7B5%7D%7D%3D%5Cboxed%7B%5Csqrt%5B5%5D%7B2%5E4%7D%3D%28%5Csqrt%5B5%5D%7B2%7D%29%5E4%7D)
__
In many cases, it is preferred to keep the power inside the radical symbol.
Answer:
No
Step-by-step explanation:
the radius squared is 49 times π, which is roughly 3 means the area of the base is roughly 150 ft².
This means that one third of the height cannot be more than 100 / 150 = 2/3 of a foot. That makes the height about 2 ft, much less than the reported 25 ft.
52/38 = 1.368
1.368 x 63 = 86.21
tree is 86.2 feet high
The mass of an object will never change no matter what, however, the weight relies on gravity. So therefore, the answer would be D.
