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sineoko [7]
2 years ago
8

Solve the equation 2h^2-5=27

Mathematics
1 answer:
maksim [4K]2 years ago
6 0

Answer: h= 4, h=-4

step by step-2h^2-5=27

2h^2-5-27=2ℎ2−5−27=0

2h2−5−27=0

2ℎ2−32=0

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What is the simplify answer to 4 3/5 + 15 ÷ 1/5 =​
Tasya [4]

Answer:

79.6

Step-by-step explanation:

4 3/5+15÷1/5

23/5+15÷1/5

4.6+15÷0.2

4.6+75

79.6

6 0
2 years ago
Two shops, Waitroze and Budgins sell the same brand of cans of soup but with different offers.
Goshia [24]

Answer:

24 cans at Waitrose would be £10.05.

24 cans at Budgins would be £11.56.

Step-by-step explanation:

Times the waitrose offer by 3

Times the budgins offer by 4

Hope that helped. x

6 0
2 years ago
Vectors: Find the vector from the point A=(−1,−7,3) to the point B=(3,−2,9).
devlian [24]

Answer:

\overrightarrow {AB} = (4,5,6)

1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F

2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F

3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T

4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F

5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F

Step-by-step explanation:

The vector AB is the vectorial difference between point A and B, that is:

\overrightarrow {AB} = \vec B - \vec A

Given that \vec A = (-1,-7,3) and \vec B = (3,-2,9), the vector AB is:

\overrightarrow {AB} = (3,-2,9)-(-1,-7,3)

\overrightarrow{AB} = (3-(-1),-2-(-7),9-3)

\overrightarrow {AB} = (4,5,6)

The vectorial equation of the line is represented by:

\langle x, y, z\rangle = \vec A + t \cdot \overrightarrow {AB}

Where t is the parametric variable, dimensionless. Given that \vec A = (-1,-7,3) and \overrightarrow {AB} = (4,5,6)

\langle x,y,z \rangle = \langle -1,-7,3 \rangle + t\cdot \langle 4,5,6 \rangle

Finally, the list of questions are now checked:

1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F

2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F

3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T

4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F

5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F

4 0
2 years ago
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