Factor the coefficients:
-12=(-1)(3)(2^2)
-9=(-1)(3^2)
3=3
The greatest common factor (GCF) is 3
Next we find the GCF for the variable x.
x^4
x^3
x^2
The GCF is x^2.
Next GCF for variable y.
y
y^2
y^3
the GCF is y
Therefore the GCF is 3x^2y
To factor this out, we need to divide each term by the GCF,
(3x^2y)(−12x4y/(3x^2y) − 9x3y2/(3x^2y) + 3x2y3/(3x^2y) )
=(3x^2y)(-4x^2-3xy+y^2)
if we wish, we can factor further:
(3x^2y)(y-4x)(x+y)
Hello from MrBillDoesMath!
Answer:
5.06
Discussion:
Angle J = 180 - (120 + 40) = 180 - 160 = 20 degrees,
From the law of sines
sin(120)/k = sin(20)/2 =>
sin(120) = k * ( sin(20)/2) ) (multiply both sides by "k")
k = sin(120)/ ( sin(20)/2) (divide both sides by sin(20)/2)
k = (0.866) / ( 0.171) = 5.06
Regards,
MrB
P.S. I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!
Answer:
The even numbers between 0 and X represents an arithmetic sequence with a common difference of 2
The rule of arithmetic sequence = a + d(n - 1)
Where a is the first term and n is the number of terms
So, for the even numbers between 0 and X
The first term = a = 0
d = 2
So, we need to find n at the last term which is X
∴ X = 0 + 2 ( n -1 )
∴ n - 1 = X/2
∴ n = X/2 + 1
The sum of the arithmetic sequence = (n/2) × (2a + (n−1)d)
Substitute with a and d and X
So, the sum = (n/2) * (2*0 + (n−1)*2)
= (n/2) * ((n−1)*2)
= n(n-1)
= (X/2 + 1) * (X/2)
= X/2 by (X/2 + 1)
So, The quick way to add all even numbers between 0 and X always works.
