4 years ago

Please help me with number 53.

Mathematics

1 answer:

zimovet [89]4 years ago

7 0

$\dfrac{3\sqrt7+1}{\sqrt5}=\dfrac{(3\sqrt7+1)\cdot\sqrt5}{\sqrt5\cdot\sqrt5}=\dfrac{3\sqrt{35}+\sqrt5}{5}$

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Simplify the algebraic expression:<br><br> -4h + 8 + 9h - 1 + 3h - 7

skad [1K]

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-4h + 8 + 9h - 1 + 3h - 7= 8h

Step-by-step explanation:

8 0

3 years ago

Please solve this question fast.

Alexxandr [17]

Answer:

See Explanation

Step-by-step explanation:

${a} = {6}^{x}, \: \: b = {6}^{y} ...(given) \\ {a}^{y}. {b}^{x} = 36..(1) \\ pluggig \: the \: values \: of \: a \: and \: b \: in \: (1) \\ ({6}^{x}) ^{y} . ({6}^{y}) ^{x} = {6}^{2} \\ {6}^{xy}.{6}^{xy} = {6}^{2} \\ {6}^{xy + xy} = {6}^{2} \\ {6}^{2xy} = {6}^{2} \\ bases \: are \: equal \: so \: exponentes \: will \: also \: be\\ \: equal \\ \therefore \: 2xy = 2 \\ xy = \frac{2}{2} \\ \huge \red { \boxed{ xy = 1}} \\ hence \: proved \\$