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pishuonlain [190]
2 years ago
10

How do you find the solution set for -x^2+6x<0?

Mathematics
1 answer:
aliina [53]2 years ago
6 0
-x^2+6x\ \textless \ 0\\&#10;-x(x-6)\ \textless \ 0\\&#10;x\in(-\infty,0)\cup(6,\infty)&#10;
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Please answer this correctly if you can. No Links. Thank you
Semmy [17]

Answer:

y=x+3

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y=x+2

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Step-by-step explanation:

- For Y=X+3 it could be any point for Y as long as X is 3 less than Y.

- For Y=X+3 it could be any point for X and long as Y is 3 more than X.

- For Y=X+2 it could be any point for Y as long as X is 2 less than Y.

- For Y=X+2 it could be any point for X and long as Y is 2 more than X.

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kobusy [5.1K]

Answer:

2 sqaured

Step-by-step explanation:

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riadik2000 [5.3K]
F(3) = 6 - 3 = 3

answer 3
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Irina18 [472]
Your answer should be C :-)
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Which of the following is a polynomial with roots 3, 5i, and −5i?
jek_recluse [69]
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==================================
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<em>"Associate with people who are likely to improve you."</em>
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