Answer:
<u>Given circle:</u>
The center is at (4, 0) and the radius is 5 units
<u>Lets find the distance from (7, 2) to the center of the circle:</u>
- <u />
![d = \sqrt{(7 - 4)^2 + (2 - 0)^2} = \sqrt{9+4} = \sqrt{13} < 5](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%287%20-%204%29%5E2%20%2B%20%282%20-%200%29%5E2%7D%20%20%3D%20%5Csqrt%7B9%2B4%7D%20%3D%20%5Csqrt%7B13%7D%20%3C%205)
Since d < 5, the point (7, 2) lies <u>inside</u> the circle
Answer:
Not enough info given
Step-by-step explanation:
There isn’t a accurate slope to find if they are parallel or perpendicular
Answer:
The second graph is the correct graph
Step-by-step explanation:
4x + 2 - 3x + 5 - 2(x + 5) = (2x - 5) + (3x + 4)
4x + 2 - 3x + 5 - 2x - 10 = 2x - 5 + 3x + 4
4x - 3x - 2x + 5 + 2 - 10 = 2x + 3x - 5 + 4
- x - 3 = 5x - 1
-x - 3 = 5x - 1 is the line above recopied
+x = +x
-3 = 6x - 1
<span> +1 = + 1 </span>
- 2 = 6x
- 2/6 = 6x/6
- 1/3 = x, the answer
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![\diamond\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}\diamond](https://tex.z-dn.net/?f=%5Cdiamond%5Clarge%5Cblue%5Ctextsf%7B%5Ctextbf%7B%5Cunderline%7B%5Cunderline%7BQuestion%3A-%7D%7D%7D%7D%5Cdiamond)
Write an equation for the line that passes through (0, 1) and has a slope of 2 (in point-slope form).
![\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}\diamond](https://tex.z-dn.net/?f=%5Cdiamond%5Clarge%5Cblue%5Ctextsf%7B%5Ctextbf%7B%5Cunderline%7B%5Cunderline%7BAnswer%20and%20How%20to%20Solve%3A-%7D%7D%7D%7D%5Cdiamond)
<u>Point-slope form</u>:-
![\sf{y-y_1=m(x-x_1)}](https://tex.z-dn.net/?f=%5Csf%7By-y_1%3Dm%28x-x_1%29%7D)
Substitute 1 for y₁, 2 for m, and 0 for x₁:-
So we conclude that Option B is correct.
<h3>Good luck.</h3>
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