Answer:
The real zeros of f(x) are x = 0.3 and x = -3.3.
Step-by-step explanation:
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots 
such that 
, given by the following formulas:
In this problem, we have that:
So
The real zeros of f(x) are x = 0.3 and x = -3.3.
Answer: 106 degrees. Don’t listen to the guy who said 88.
Step-by-step explanation: Found the answer on Khan Academy.
Answer:
1: Rhombus
2: Square
3: Rectangle
4: Trapezoid (isosceles trapezoid to be exact)
Answer:
we have to find the quotient and the remainder when (x³ + 5x + 3x² + 5x³ + 3) is divided by (x² + 4x + 2) ♥9 dividend = x² + 4x + 2 using Euclid division lemma, x² + 4x + 2) x² + 5x³ + 3x² + 5x + 3(x³ - 4x² + 19x - 65 x² + 4x² + 2x³ - 4x² + 3x² + 3x² - 4x*-16x³8x² 19x³ + 11x² + 5x 19x³ +76x² + 38x -65x²-33x + 3 -65x²-260x - 130 +227x + 133 Therefore the quotient is x² - 4x + 19x - 65 and remainder is 227x + 133
