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2 years ago

7

the sum of the first four terms of an A.p is 62.if the difference between 4 terms and 2nd terms is 14. find the first term and c

ommon difference

1 answer:

Oksana_A [137]2 years ago

3 0

Answer:

-2 -4 -6 -8

Step-by-step explanation:

I got the answer off of khan academy

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Use the distributive property to multiply 34x6 , 16x9 , 27x8

iragen [17]

6x30+6x4

9x10+9x6

8x20+8x7

hope this helps

6 0

3 years ago

5x +6y = 20 (1)

slega [8]

(2) + (2)

=> 8x - 6y = -46 ———(3)

(1) + (3)

=> 5x + 6y + (8x - 6y) = 20 - 46

=> 13x + (6-6)y = -26

=> 13x + 0y = -26

=> 13x = -26

=> x = -26/13

=> x = -2

=> 5(-2) + 6y = 20

=> 6y = 20 + 10

=> 6y = 30

=> y = 5

x = -2, y = 5 => C

4 0

2 years ago

Read 2 more answers

tại một cửa hàng , xác suất để khách hàng mua thiết bị điện tử là 0,3, xác suất để khách hàng cài đặt phần mềm là 0,4 nhưng với

Harrizon [31]

Answer:

http://eldata2.neu.topica.vn/TXTOKT02/Giao%20trinh/03_NEU_TXTOKT02_Bai2_v1.0014109205.pdf

Step-by-step explanation:

8 0

2 years ago

Which of the binomials below is a factor of this trinomial 3x^2+18-21

KengaRu [80]

Answer:

A

Step-by-step explanation:

you will get 3(x-1)×(x+1) you can get the 3 and x by itself then it would be x+3

4 0

3 years ago

Which expressions are equivalent??

Brilliant_brown [7]

<u>Given</u>:

The given expression is $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$

We need to determine the equivalent expression.

<u>Option A:</u> -1

Solving the expression, we get;

$\frac{3}{2} x+14-\frac{3}{2} x+15$

Simplifying, we get;

$14+15=29$

Thus, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is not equivalent to -1.

Hence, Option A is not the correct answer.

<u>Option B</u>: 29

Solving the expression, we get;

$\frac{3}{2} x+14-\frac{3}{2} x+15$

Simplifying, we get;

$14+15=29$

Thus, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is equivalent to 29.

Hence, Option B is the correct answer.

<u>Option C</u>: $2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]$

Let us rewrite the given expression.

$2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]$

Thus, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is equivalent to $2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]$

Thus, Option C is the correct answer.

<u>Option D</u>: $2\left(\frac{3}{4} x\right)+2(7)+3\left(\frac{1}{2} x\right)+3(-5)$

Rewriting the expression, we get;

$2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]$

Hence, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is equivalent not to $2\left(\frac{3}{4} x\right)+2(7)+3\left(\frac{1}{2} x\right)+3(-5)$

Thus, Option D is not the correct answer.

<u>Option E:</u> $2\left(\frac{3}{4} x\right)+2(7)+(-3)\left(\frac{1}{2} x\right)+(-3)(-5)$

Multiplying the terms within the bracket, we get;

$2\left(\frac{3}{4} x\right)+2(7)+(-3)\left(\frac{1}{2} x\right)+(-3)(-5)$

Hence, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is equivalent to $2\left(\frac{3}{4} x\right)+2(7)+(-3)\left(\frac{1}{2} x\right)+(-3)(-5)$

Thus, Option E is the correct answer.

4 0

3 years ago