Probability of rolling a 6 with two dice one with values 1, 2, 2, 3, 3, 4 and 1, 3, 4, 5, 6, 8
777dan777 [17]
Answer:
11/12 chance of the probability of rolling a 6 with 2 dice
Answer:
Step-by-step explanation:
0.5*0.5*0.5*0.5 = 0.0625
(probability of tail) *(probability of tail) *(probability of head) *(probability of head)
Answer:
-2
Step-by-step explanation:
z - 7 ≥ 0
z ≥ 7
| z - 7 | = z - 7, z ≥ 7
| z - 7 | = -z + 7, z < 7
z - 9 ≥ 0
z ≥ 9
| z - 9 | = z - 9, z ≥ 9
| z - 9 | = -z + 9, z < 9
| z - 7 | = -z + 7
| z - 9 | = -z + 9
|z - 7| - |z - 9|
-z + 7 - (-z + 9)
-z + 7 + z - 9
= -2
22 + 23 = 45
Largest would be 23
1) You must do division first. So divide 5/12 and get .41666666...
2) Then you add 15+5 and get 20.
3) Finally you subtract 20 and .41666666... and you get 19.5833333...
4) you can simplify 19.583333... to 19.584 if you need to.
