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DanielleElmas [232]
3 years ago
6

A country's population in 1990 was 132 million. In 1998 it was 137 million. Estimate the population in 2003 using the exponentia

l growth formula. Round your answer to the nearest million.
Mathematics
1 answer:
Likurg_2 [28]3 years ago
8 0
140 million.I guess.
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59. What happens to the graph of y = |x| when the equation changes to y = |x + 4? A The graph shifts up 4 units. The graph shift
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Answer: Graph shifts 4 units to the left

Explanation:

I'm assuming you meant to say y = |x+4|

If so, then the graph shifts 4 units to the left. Replacing x with x+4 moves the xy axis 4 units to the right if we held the V shape in place (since each x is now 4 units larger). This gives the illusion the V shape is moving 4 units to the left.

Or you could look at the vertex point to see how it moves. On y = |x|, the vertex is at (0,0). It then moves to (-4,0) when we go to y = |x+4|

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Marco is carrying two cylinder-shaped cans. Each can has the same height
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Answer:

Choice D

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A spring stretches in relation to the weight hanging from it all cording to the equation Y equals 0.75X +0.25 where X is the wei
Tomtit [17]
What is the question?
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2 years ago
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Please help! How on earth do I do this? In the year 2015, Anna bought a new car for $36,000. In 2017, she was told that the valu
Klio2033 [76]

Part A

Purchase Value of Anna's Car in 2015 = $36,000

Depreciated Value of Anna's Car in 2017 = $25,000

We know that the value of the car is depreciating linearly.


From the above data, we can see that the value of the car has reduced by $36,000-$25,000 = $11,000 over 2 years.

⇒ Per year the value has been depreciated by \frac{11000}{2}

⇒ Per year the value has been depreciated by $5,500

So if the value of a car in 2015 is V₀ then value of the car after t years can be determined by the below function:

V (t) = V₀ - (t*5,500), where t indicates the years passed since 2015

OR V (t) = 36,000 - (t*5,500), where t indicates the years passed since 2015

Part B

Suggested value of Anna's car for trade in option in 2018 = $15,000

In 2018, 3 years would have been passed since 2015. Using the value of t = 3 in the function determined in Part A:

V(3) = V₀ - (3*5,500)

⇒ V(3) = 36,000 - (16,500)

⇒ V(3) = $19,000

From the above calculations, we can see that the value of the car in 2018 should be $19,000, however the suggested value for trade in is indicated as $15,000 which is lower than what the value of the car should be. Hence, basis linear depreciation, the $15,000 value is not fair for the car in 2018.

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