2) Regina and Gino each had a piece of string. Regina's string measured inches long. Gino's string measured inches long. How muc
h longer was Regina's string compared
12
to Gino's string?
A) // inches
B) { inches
3
o
3
inches
D)
12
inches
Please help. It’s 3:55 rn and I spent 20 mins on this test. December 2nd :(
1 answer:
Using subtraction of fractions, it is found that Regina's string was
inches longer compared to Gino's string.
- If the subtraction of two measures of length a and b is positive, it represents how much longer a is than b.
In this problem:
- Regina's string is
inches long.
- Gino's string is
inches long.
Then:

Regina's string was
inches longer compared to Gino's string.
To learn more about subtraction of fractions, you can check brainly.com/question/13197173
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hope this help Answer:( x - 3i√2)(x + 3i√2)
solve x² + 18 = 0
x² = - 18 ⇒ x = ±√- 18 = ±3i√2
factors are ( x - (3i√2))(x - (-3i√2))
x² + 18 = (x - 3i√2)(x + 3i√2
Step-by-step explanation:
Answer:
D. (2x)(3x) + 5(3x - 2)
<em>good luck, i hope this helps :)
</em>
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So that mean 12x12=144quarter cm
The equation for this should be 4n - 15