Step-by-step explanation:
we have
length =8in
breadth =6in
since . The length and width of the actual flower bed will be 24 times larger than the length and width in the drawing.
new
length=8×24=192in
breadth =6×24=144in
(b) What is the perimeter of the actual flower bed ? Show your work.
<em>answer:the perimeter of the</em><em> </em><em>actual flower bed</em><em> =2(l+b)</em>
<em> =2(l+b)=2(192+144)=672</em><em>in</em>
(a) What is the perimeter of the drawing? Show your work
<em>answer</em><em> </em><em>:</em><em> </em><em>the perimeter of the </em><em>drawing</em>
<em>=</em><em>2</em><em>(</em><em>8</em><em>+</em><em>6</em><em>)</em><em>=</em><em>9</em><em>6</em><em>in</em>
<em>(c) What is the effect on the perimeter of the flower bed with the dimensions are multiplied by 24? Show your work</em>
<em>p</em><em>e</em><em>r</em><em>i</em><em>m</em><em>e</em><em>t</em><em>e</em><em>r</em><em> </em><em>o</em><em>f</em><em> </em><em>flower </em><em>bed</em><em> </em><em>/</em><em>p</em><em>e</em><em>r</em><em>i</em><em>m</em><em>e</em><em>t</em><em>e</em><em>r</em><em> </em><em>o</em><em>f</em><em> </em><em>d</em><em>r</em><em>a</em><em>w</em><em>i</em><em>n</em><em>g</em>
<em>=</em><em>9</em><em>6</em><em>/</em><em>6</em><em>7</em><em>2</em><em>=</em><em>1</em><em>/</em><em>7</em>
<h3>
<em>perimeter</em><em> </em><em>of</em><em> </em><em>drawing</em><em> </em><em>is</em><em> </em><em>increased</em><em> </em><em>by</em><em> </em><em>7</em><em>t</em><em>i</em><em>m</em><em>e</em><em>s</em><em> </em><em>of</em><em> </em><em>perimeter</em><em> </em><em>of</em><em> </em><em>flower</em><em> </em><em>bed</em></h3>
The answer i came up with is A.
Answer:
<h2>A. m∠A = m∠O </h2>
Step-by-step explanation:
Answer:
it would be 3
Step-by-step explanation:
anything above 5, goes to the nearest, (in this case, whole number)
so it would be 3. hope this helped
Answer:
y² + y + 
= (y + 
)²
Step-by-step explanation:
In most cases, we can factor a polynomial, or quadratic, by looking at the factors of the last term. In this case, the last term is . When we factor a polynomial, we are looking for two expressions that when multiplied together using FOIL (forward-outside-inside-last) will give us the polynomial. For example: (a + b)(a + b) or (a+ b)².
In order to get y² + y + , we are looking for a 'c' value that will add up to '1' which is our 'b' value (ay² + by + c).
Since 
Then, we can use as our factor for both expressions. Putting this together we get: (y + )(y + ) or (y + )²
