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Sphinxa [80]
3 years ago
12

Taking test need answers ​

Mathematics
1 answer:
kati45 [8]3 years ago
3 0

Answer:

It's a test!!!

sorry if it's a test I can't help ya dude.

Step-by-step explanation:

but still.

I hope you get more answers?

You might be interested in
Two angles are complements if their sum is 90 degrees. The measure of one angle is one third the measure of its complement. Find
zysi [14]

Answer:

22.5 degrees

Step-by-step explanation:

90 = x + 3x

90 = 4x (divide by 4)

22.5 = x

22.5 + 67.5 = 90

5 0
3 years ago
show whether each equation has one solution, infinitely, many solutions or no solutions: 2x+7=-8x-9+10x​
alexira [117]

Answer:

  1. The statement is <em>false</em>
  2. There is<em> no solution</em>

Step-by-step explanation:

Step 1: <em>Collect the like terms</em>

2x+7 = -8x-9+10x

2x+7 = 2x-9

Step 2: <em>Cancel</em><em> </em><em>equal</em><em> </em><em>terms</em><em> </em><em>of</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>equation</em>

2x+7 = 2x-9

7 = -9

Result: The statement is <em>false</em> and there is <em>no solution</em> as 7 is <em>not equal</em> to -9.

I hope this helped ! ;)

3 0
3 years ago
Write the standard equation for the circle 30. Center (2,7), r=4. 31. Center (-6,-8), that passes treough (0,0)
Salsk061 [2.6K]
The standard equation of the circle is:

(x-h)^2+(y-k)^2=r^2 where (h,k) it the center of the circle and r is the radius...

so

30.

(x-2)^2+(y-7)^2=16

31.

We need to find the radius...(I'll just use the Pythagorean Theorem)

r^2=6^2+8^2

r^2=36+64

r^2=100  (so the radius is 10) and its center is (-6,-8) so

(x+6)^2+(y+8)^2=100
3 0
4 years ago
PLSSSSSSS HELPPPPPPPP ASAPPPP
Ivanshal [37]

Answer:

Answer should be choice 4

Step-by-step explanation:

4 0
3 years ago
A student claims that the rectangular point below can be represented by the
Sladkaya [172]

Since we don't have a figure we'll assume one of them is right and we're just being asked to check if they're the same number.  I like writing polar coordinates with a P in front to remind me.

It's surely false if that's really a 3π/7; I'll guess that's a typo that's really 3π/4.

P(6√2, 7π/4) = ( 6√2 cos 7π/4, 6√2 sin 7π/4 )

P(-6√2, 3π/4) = ( -6√2 cos 3π/4, -6√2 sin 3π/4 )

That's true since when we add pi to an angle it negates both the sine and the cosine,

cos(7π/4) = cos(π + 3π/4) = -cos(3π/4)

sin(7π/4) = sin(π + 3π/4) = -sin(3π/4)

Answer: TRUE

3 0
3 years ago
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