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Over [174]
3 years ago
5

B) Solve x + 5x – 14 = 0

Mathematics
2 answers:
melomori [17]3 years ago
6 0

Answer:

2 1/3

Step-by-step explanation:

Step 1:

x + 5x - 14 = 0      Equation

Step 2:

6x - 14 = 0      Combine Like Terms

Step 3:

6x = 14      Add 14 on both sides

Step 4:

x = 14 ÷ 6        Divide

Answer:

x =  2 1/3

Hope This Helps :)

Nastasia [14]3 years ago
4 0
5x+x=14
14/6= 2.3
x=2.3
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A triangle has side lengths of 7 in., 9 in., and 11 in. Determine whether this is a right triangle and why.
Harlamova29_29 [7]

Answer:

Not a right triangle.  See below for my reasoning.


Step-by-step explanation:

If this is a right triangle, then the sum of the squares of the two shorter sides will equal the square of the longest side:  7^2 + 9^2 = 11^2 => 49 + 81 = 121   But this is false.

8 0
3 years ago
A quiz-show contestant is presented with two questions, question 1 and question 2, and she can choose which question to answer f
Mrrafil [7]

Answer:

The contestant should try and answer question 2 first to maximize the expected reward.

Step-by-step explanation:

Let the probability of getting question 1 right = P(A) = 0.60

Probability of not getting question 1 = P(A') = 1 - P(A) = 1 - 0.60 = 0.40

Let the probability of getting question 2 right be = P(B) = 0.80

Probability of not getting question 2 = P(B') = 1 - P(B) = 1 - 0.80 = 0.20

To obtain the better option using the expected value method.

E(X) = Σ xᵢpᵢ

where pᵢ = each probability.

xᵢ = cash reward for each probability.

There are two ways to go about this.

Approach 1

If the contestant attempts question 1 first.

The possible probabilities include

1) The contestant misses the question 1 and cannot answer question 2 = P(A') = 0.40; cash reward associated = $0

2) The contestant gets the question 1 and misses question 2 = P(A n B') = P(A) × P(B') = 0.6 × 0.2 = 0.12; cash reward associated with this probability = $200

3) The contestant gets the question 1 and gets the question 2 too = P(A n B) = P(A) × P(B) = 0.6 × 0.8 = 0.48; cash reward associated with this probability = $300

Expected reward for this approach

E(X) = (0.4×0) + (0.12×200) + (0.48×300) = $168

Approach 2

If the contestant attempts question 2 first.

The possible probabilities include

1) The contestant misses the question 2 and cannot answer question 1 = P(B') = 0.20; cash reward associated = $0

2) The contestant gets the question 2 and misses question 1 = P(A' n B) = P(A') × P(B) = 0.4 × 0.8 = 0.32; cash reward associated with this probability = $100

3) The contestant gets the question 2 and gets the question 1 too = P(A n B) = P(A) × P(B) = 0.6 × 0.8 = 0.48; cash reward associated with this probability = $300

Expected reward for this approach

E(X) = (0.2×0) + (0.32×100) + (0.48×300) = $176

Approach 2 is the better approach to follow as it has a higher expected reward.

The contestant should try and answer question 2 first to maximize the expected reward.

Hope this helps!!!

3 0
3 years ago
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