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VLD [36.1K]
3 years ago
14

What if someone has 8 necklaces .One fourth of the necklace are blue .How many necklaces are blue?

Mathematics
2 answers:
ehidna [41]3 years ago
8 0
2 lecklases are blue because 1/4 of 8 is 2 thanks your answer i have to keep this going in order to answer and there
Paraphin [41]3 years ago
4 0
It is 2 blue <span>necklaces </span>
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HELP 100 POINT FAST (NO WRONG ANSWER) + BRAINLIEST TO WHO EVER ANSWERS FIRST U^U
Ahat [919]

Answer:

\Large \boxed{\sf A}

Step-by-step explanation:

\displaystyle \left(\frac{2}{3}\right)^4

<em>n</em>  → exponent, means to multiply the base number by itself <em>n  </em>no. of times.

Here we multiply the base number by itself 4 times.

\displaystyle \frac{2}{3}\cdot \frac{2}{3}\cdot \frac{2}{3}\cdot \frac{2}{3}

8 0
3 years ago
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Which equation could be used to find the value of x in the triangle below?
valkas [14]

Answer:

  • 4x - 12 = 180

Step-by-step explanation:

<u>Sum of the angles of triangle equals 180</u>

  • x + 12 + 2x - 29 + x + 5 = 180

<u>Simplified</u>

  • 4x - 12 = 180
5 0
3 years ago
The difference of two numbers is 10. Their sum is 23. Find the numbers.
Vika [28.1K]

Answer:

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4 0
3 years ago
Sherman goes golfing every 6^\text{th}6 th 6, start superscript, start text, t, h, end text, end superscript day and Brad goes g
nydimaria [60]

Answer:

In every 42 days,  Sherman and Brad will go golfing on the same day.

Step-by-step explanation:

Given:

Sherman goes golfing every 6th day.

Brad goes golfing every 7th day.

If they both went golfing today, we need to determine how many days unit they will go golfing on the same day again.

Solution:

In order to determine how many days unit Sherman and Brad will go golfing on the same day again, we will take least common multiple of 6 and 7.

To find least common multiple of 6 and 7, we will list out their multiples.

6=6,12,18,24,30,36,42

7=7,14,21,28,35,42

We find out that the least common multiple of 6 and 7 =42.

Thus, we can conclude that Sherman and Brad will go golfing on same days on every 42nd day after they meet..

7 0
4 years ago
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HELP
Sonbull [250]

Answer:

A. 121 ⇒ III. 11

B. 64 ⇒ II. 4 and IV. 8

C. 27 ⇒ I. 3

D. 125 ⇒ V. 5

E. 16 ⇒ II. 4

Step-by-step explanation:

Let us find the correct answer

∵ 121 = 11 × 11

∴ The square root 121 is 11

∴ A. 121 ⇒ III. 11

∵ 64 = 8 × 8

∴ The square root of 64 is 8

∵ 64 = 4 × 4 × 4

∴ The cube root of 64 is 4

∴ B. 64 ⇒ II. 4 and IV. 8

∵ 27 = 3 × 3 × 3

∴ The cube root of 27 is 3

∴ C. 27 ⇒ I. 3

∵ 125 = 5 × 5 × 5

∴ The cube root of 125 is 5

∴ D. 125 ⇒ V. 5

∵ 16 = 4 × 4

∴ The square root of 16 is 4

∴ E. 16 ⇒ II. 4

5 0
3 years ago
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