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3 years ago

The sum of two numbers is 48 and the difference is 4. what are the numbers?

Mathematics

1 answer:

alexandr1967 [171]3 years ago

5 0

Answer:

22 and 26

Step-by-step explanation:

48-4= 44

44÷2= 22 (first no.)

22+4= 26 (second no.)

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Sedaia [141]

Answer:

Option (B). Perimeter of the quadrilateral ABCD= 14.6 units

Step-by-step explanation:

From the figure attached,

Coordinates of the vertices are A(3, 5), B(1, 3), C(3, -1), D(5, 3).

Length of AB = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

= $\sqrt{(3-1)^2+(5-3)^2}$

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= $\sqrt{8}$

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Length of BC = $\sqrt{(1-3)^2+(3+1)^2}$

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= 4.47 units

Perimeter of the quadrilateral = AB + AD + DC + BC

= 2.83 + 2.83 + 4.47 + 4.47

= 14.6 units

Option (B) is the answer.

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Step-by-step explanation:

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3 years ago

The sum of two numbers is 48 and the difference is 4. what are the numbers?​

The sum of two numbers is 48 and the difference is 4. what are the numbers?