3 years ago

Whats the answer to this? Please help.

Mathematics

1 answer:

BaLLatris [955]3 years ago

7 0

Answer:

The answer is just 1 and 3.

Step-by-step explanation:

To understand this problem, you must think of what whole numbers actually are.

Whole numbers consist of Positive integers and Zero.

Positive integers include 1, 2, 3, 4, 5, 6, ... etc

Zero is 0

The reason $\frac{23}{5}$ isn't a whole number is because that fraction doesn't reduce any further and does not yield a whole number.

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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B80%7D%20" id="TexFormula1" title=" \sqrt[3]{80} " alt=" \sqrt[3]{80} " ali

Marianna [84]

Start by decomposing the number inside the root into primes

Then group the terms into cubes if possible

$\begin{gathered} 80=2\cdot2\cdot2\cdot2\cdot5 \\ 80=2^3\cdot2\cdot5 \\ 80=10\cdot2^3 \end{gathered}$

rewrite the root

$\sqrt[3]{80}=\sqrt[3]{10\cdot2^3}$

then cancel the terms that are cubes and bring them out of the root

$\sqrt[3]{80}=2\sqrt[3]{10}$

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