Answer:
Both air balloon and water balloon data are best modeled by an exponential function.
Step-by-step explanation:
Air balloon
Time (seconds) Volume (cubic centimeters)
0 95
3 69
6 50
9 37
12 27
The relation Volume variation/time is constant for lines, In this case, this value change from point to point, as can be seen next.
(69 - 95)/3 = -8.67
(50 - 69)/3 = -6.33
(37 - 50)/3 = -4.33
(27 - 37)/3 = -3.33
Water balloon
Time (seconds) Volume (cubic centimeters)
0 30
3 15.8
6 7.8
9 4
12 2
(30 - 15.8)/-3 = -4.73
(15.8 - 7.8)/-3 = -2.67
(7.8 - 4)/-3 = -1.27
(4 - 2)/-3 = -0.67
In this case, the relation Volume variation/time also change from point to point.
Then, both air balloon and water balloon data are best modeled by an exponential function.
Since the diameter of the cylinder is 10, its radius is half that, or 5, thus
It should be 11. hope this helps :)
Answer:
Step-by-step explanation:
The shaded area is the difference of the large and small squares.
<u>Area of large square:</u>
<u>Area of small square:</u>
<u>Shaded area:</u>
- A = A(l) - A(s)
- A = (y + 4)² - y² = y² + 8y + 16 - y² = 8y + 16
