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astra-53 [7]
1 year ago
10

Helppppppppppppp i need this homework done by today

Mathematics
1 answer:
lbvjy [14]1 year ago
7 0

Answer: 13. -68

14. 36

15. -36

16. -3

17. 10

18. -4

19. 1310 ft

20. 330 ft

Step-by-step explanation:

13. 34*(-2)=-68

14. -9*(-4)=

-(9*(-4))=

-(-36)=36

15. 12*(-3)=-36

16. -12/4=-3

17. -20/(-2)=

20/2=10

18. 200/(-50)=-4

19. -1640*(-1)-(-330*(-1))=

1640-(-330*(-1))=

1640-330=1310 ft

20. -990*(-1)-(-660*(-1))=

990-(-660*(-1))=

990-660=330 ft

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Nvm the questions change if anyone wants these points then your free to have em
sasho [114]

Answer:

ok thanks :)

Step-by-step explanation:

4 0
3 years ago
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No idea how to do this equation. Its applying system's of linear equations.
icang [17]
What you want to do is take one of the 2 equations and isolate one variable. you will then use the value that you find for the variable and plug it back into the other equation. here is how:

This would be easiest to do with the second equation in the set since the x is not being multiplied by anything. So lets isolate the x in the second equation.

add 0.9y to both sides and you get:

x=4.5+0.9y

we now know what x is equal to in terms of y. so lets replace the x in the first equation with the new value. You get:

1.5(4.5+0.9y)-1.9y=-29

Now just solve for y:
6.75+1.35y-1.9y=-29
1.35y-1.9y=-35.75
-0.55y=-35.75
y=65

so now you know that y=65 so plug 65 in as y in the second equation to find x

x-0.9*65=4.5

Now simply solve for x

x-(-58.5)=4.5
x+58.5=4.5
x=-54

Hope this helped! :)



3 0
3 years ago
PLEASE HELP ANSWER THESE QUESTIONS!
Sliva [168]

Answer:

Step-by-step explanation:

a² - b² = (a+ b)(a - b)

1) (2n-4/2n) ÷ (n^2-4/n)

=\frac{2n-4}{2n}*\frac{n}{n^{2}-4}\\\\=\frac{2n-2*2}{2n}*\frac{n}{n^{2}-2^{2}}\\\\=\frac{2*(n-2)}{2n}*\frac{n}{(n+2)*(n-2)}\\\\=\frac{1}{n+2}

2) [y^2-36/y^2-49] ÷[ y+6/y-7]

=\frac{y^{2}-36}{y^{2}-49}*\frac{y-7}{y+6}\\\\=\frac{y^{2}-6^{2}}{y^{2}-7^{2}}*\frac{y-7}{y+6}\\\\=\frac{(y+6)*(y-6)}{(y+7)*(y-7)}*\frac{y-7}{y+6}\\\\=\frac{y-6}{y+7}\\

3) [m^2-1/ m^2-m] ÷ [m^2-7m-8/3m ]

=\frac{m^{2}-1}{m^{2}-m}*\frac{3m}{m^{2}-7m-8}\\\\=\frac{(m+1)*(m-1)}{m*(m-1)}*\frac{3m}{(m-8)*(m+1)}\\\\=\frac{3}{m-8}

Hint :  m² - 7m - 8

sum = -7

Product  = -8

Factor = (-8), 1

m² - 7m - 8  =m² - 8m + m - 8

                   = m*(m - 8) + (m-8)

                   = (m - 8)(m +1)

7 0
3 years ago
Chinedu sat down to do his homework, which included 30 math problems. He solved 2 problems each minute. Let f(n) be the number o
vova2212 [387]

Answer:

It would be an arithmetic sequence.

Step-by-step explanation:

This is because during each minute, he does another 2 problems. Or, in other words +2 each minute.

This is the result of the sequence during each minute:

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Time (Minutes) --->

If it was instead a geometric equation, it would go by a multiple, such as the number 2. Or, ×2 each minute.

During the first minute, he learns 2 problems. But then as each minutes passes it turns into 4, then 8, and etc..

This is the result of the pretend sequence during each minute:       (Problems Left): <em>30, 28, 24, 16, 0</em>

Time (Minutes) --->

The formula would be for this equation would follow

an = a1 + (n-1)d

an is your result.

a1 is the first number you plug in

(n-1) is just there, don't mind it (aka: the term position).

and d is the rate.

So just plug them in from your equation, and you would get this:

an = 30(n-1)2

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3 years ago
How do I work it out step by step y^2+5y+6
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Answer:

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Step-by-step explanation

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3 years ago
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