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MariettaO [177]
2 years ago
15

What is the value of angle k

Mathematics
1 answer:
lesantik [10]2 years ago
4 0

Answer:∠k = 121°

Step-by-step

Exterior Angle Theorem:

The measure of an exterior angle is equal to the sum of the two remote interior angles.

Add 31° and 90° to get ∠K

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Will mark brainliest if answered correctly.
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Step-by-step explanation:

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3 years ago
A strawberry farm had 7,200 plants in total, one field had 18 rows of 200 plants ; the other field had 9. Rows of
Svetradugi [14.3K]

Answer:

We have a total of 7200 plants.

The plants are distributed in one field with 18 rows of 200 plants and another field with 9 rows of N plants.

Where we want to find the value of N.

The total number of plants in the rows is:

"number of rows times number of plants in each row."

Then the total number of plants is:

18*200 + 9*N

And we know that we have a total of 7200 plants, then:

18*200 + 9*N = 7200

9*N = 7200 - 18*200 = 3600

N = 3600/9 = 400

Then the plants are distributed in 18 rows of 200 plants for one field, and 9 rows of 400 plants in the other field.

8 0
3 years ago
Find the area of the figure below (Do Not put the units in your answer)
Contact [7]

Answer:

54

Step-by-step explanation:

Area of rhombus= (12×9) ÷2

8 0
2 years ago
a train starting from rest moves with uniform acceleration of 5 m/s2 .find its velocity when it has travelled a distance of 1 km
Degger [83]

The velocity of a train starting from rest moves with a uniform acceleration of 5 m/s2 would be 100 m/s.

Acceleration = 5 m/s2

Distance, s = 1 km = 1000m

Intital velocity, u=0 m/s

<h3>What is the first equation of motion?</h3>

We know that, Newton's equation of motion,

s = ut+ 1/2 at^2

1000 = 0 + 1/2 x 5 x t^2

1000 = 5/2 x t^2

2000/ 5 = t^2

t = 20 s

Also,a = (v-u)/t

5 = v-0/20

100 = v

v = 100 m/s

Hence, the velocity of a train starting from rest moves with a uniform acceleration of 5 m/s2 would be 100 m/s.

Learn more about velocity here;

brainly.com/question/3491339

#SPJ1

7 0
1 year ago
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