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4 years ago

Solve for d: 6d^2+5d=1

1 answer:

7 0

Step 1: Subtract 1 from both sides.6d2+5d−1=1−16d2+5d−1=0Step 2: Factor left side of equation.(6d−1)(d+1)=0Step 3: Set factors equal to 0.6d−1=0 or d+1=0d=1/6 or d=−1Answer:d=1/6 or d=−1

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3(2x+5) = 2(3x+3). V.

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3 years ago

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Dima020 [189]

Answer:

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Step-by-step explanation:

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3 years ago

1.) What is the value of cosθ given that (−5, −4) is a point on the terminal side of θ?

jeka57 [31]

Answer:

1) C

2) D

Step-by-step explanation:

We want to find the value of cos(θ) given that (-5, -4) is a point on the terminal side of θ.

This is represented by the diagram below.

Recall that cosine is the ratio of the adjacent side to the hypotenuse.

Find the hypotenuse:

$\displaystlye \begin{aligned} a^2 + b^2 &= c^2 \\ c &= \sqrt{a^2 + b^2} \\ &= \sqrt{(4)^2 + (5)^2} \\ &= \sqrt{41}\end{aligned}$

The adjacent side with respect to θ is -5 and the hypotenuse is √41. Hence:

$\displaystyle \begin{aligned}\cos \theta &= \frac{(-5)}{(\sqrt{41})} \\ \\ &= - \frac{5\sqrt{41}}{41} \end{aligned}$

Our answer is C.

We want to find the value of sin(θ) given that (-6, -8) is a point on the terminal side of θ.

This is represented in the diagram below.

Likewise, find the hypotenuse:

$\displaystyle c = \sqrt{(-6)^2 + (-8)^2} = 10$

Sine is given by the ratio of the opposite side to the hypotenuse.

The opposite side with respect to θ is -8 and the hypotenuse is 10. Hence:

$\displaystyle \begin{aligned}\sin \theta &= \frac{(-8)}{(10)} \\ \\ &= -\frac{4}{5} \end{aligned}$

Our answer is D.

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