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nevsk [136]
4 years ago
7

Solve for d: 6d^2+5d=1

Mathematics
1 answer:
scoray [572]4 years ago
7 0
Step 1: Subtract 1 from both sides.<span><span><span><span>6<span>d2</span></span>+<span>5d</span></span>−1</span>=<span>1−1</span></span><span><span><span><span>6<span>d2</span></span>+<span>5d</span></span>−1</span>=0</span>Step 2: Factor left side of equation.<span><span><span>(<span><span>6d</span>−1</span>)</span><span>(<span>d+1</span>)</span></span>=0</span>Step 3: Set factors equal to 0.<span><span><span><span>6d</span>−1</span>=<span><span><span>0<span> or </span></span>d</span>+1</span></span>=0</span><span><span>d=<span><span><span>1/6</span><span> or </span></span>d</span></span>=<span>−1</span></span>Answer:<span><span>d=<span><span><span>1/6</span><span> or </span></span>d</span></span>=<span>−<span>1</span></span></span>
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Multiply the amount of the bill by the percentage:

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Ava makes bead necklaces. She has a total of 6048 beads. Each necklace has 24 beads. Her friend maria says that the greatest num
Rama09 [41]

The question is incomplete:

Ava makes bead necklaces. She has a total of 6048 beads. Each necklace has 24 beads. Her friend maria says that the greatest number of necklace she can make with the beads is 162. Marias. Work is shown here. Explain why Maria is incorrect and how she can find the correct answer.

Answer:

Maria is incorrect because when you divide the number of beads by the beads in each necklace, you find that she can make 252 necklaces.

Step-by-step explanation:

You can find the number of necklaces Avan can make by dividing the number of beads she has by the amount in each necklace:

6048/24=252

According to this, you can say that Maria is incorrect because when you divide the number of beads by the beads in each necklace, you find that she can make 252 necklaces.

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What is the perimeter of quadrilateral ABCD with verticals at A(-11,-6) b(-3,0) c(1,0) and d (1,-6)
dedylja [7]

<u>Answer:</u>

32 units

<u>Step-by-step explanation:</u>

We have a quadrilateral ABCD and we are given the following coordinates for these vertices:

A (-11,-6)

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C (1,0)

D (1,-6)

AB = \sqrt{(0-(-6))^2+(-3-(-11)^2} = \sqrt{36+64} =\sqrt{100} = 10 units

BC = \sqrt{(0-0)^2+(1-(-3)^2} = \sqrt{0+16} =\sqrt{16} = 4 units

CD = \sqrt{(0-(-6))^2+(1-1^2} = \sqrt{36+0} =\sqrt{36} = 6 units

AD = \sqrt{(-6-(-6))^2+(1-(-11)^2} = \sqrt{0+144} =\sqrt{144} = 12 units

Perimeter of ABCD = 10+4+6+12 = 32 units

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