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4 years ago

Solve for d: 6d^2+5d=1

1 answer:

7 0

Step 1: Subtract 1 from both sides.6d2+5d−1=1−16d2+5d−1=0Step 2: Factor left side of equation.(6d−1)(d+1)=0Step 3: Set factors equal to 0.6d−1=0 or d+1=0d=1/6 or d=−1Answer:d=1/6 or d=−1

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Two boxes of tea weight 3 oz. The Tea Time Tasty Tea Company packs 112 boxes in a case of tea. How many pounds does each case of

Marysya12 [62]

Your answer 336 because you multiply 112 x 3

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3 years ago

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The admission price was $1.00 in 1909. How much would the Speedway have had to charge in 1999 to match the purchasing power of $

olga55 [171]

Answer: 13.04

Here are some consumer price indexes from the past 100+ years:

Year CPI

1909 9.1

1919 17.3

1929 17.1

1939 13.9

1949 23.8

1959 29.1

1969 36.7

1979 72.6

1989 118.3

1999 166.6

2009 214.5

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The admission price was $1.00 in 1909. How much would the Speedway have had to charge in 1989 to match the purchasing power of $1 in 1909? In other words, how much was that in 1989?

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3 years ago

Consider the following geometric sequence: -5, 10, -20, 40,..... if the explicit formula for the sequence above is expressed in

Dima020 [189]

To solve this we are going to use the formula for the nth term of a geometric sequence: $a_{n}=a_{1}r^{n-1}$
where
$a_{n}$ is the nth term
$a_{1}$ is the first term
$r$ is the common ratio
$n$ is the place of the term in the sequence

Notice that we can infer for our problem that $B=a_{1}$ and $C=r$ .

Now, to find our common ratio, we are going to use the formula $r= \frac{a_{n}}{a_{n-1} }$
where
$a_{n}$ is the current term in the sequence
$a_{n-1}$ is the previous term in the sequence
for $a_{n}=10$ and $a_{n-1}=-5$ :
$r= \frac{10}{-5}$
$r=-2$

Since $r=C$ , we can conclude that $C=-2$ .

Notice that the first therm of our geometric sequence is -5, so $a_{1}=-5$ . Since $B=a_{1}$ , we can conclude that $B=-5$ .

We can conclude that the values of B and C in our geometric sequence are: $B=-5$ and $C=-2$ .

6 0

4 years ago

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The graph of y=f(x) is shown below. According to the graph, what is f(0)?

stepladder [879]

from,

y = f(x)

then,

f(0)

this means that x = 0

from the graph x = 0 is found at C

y = -2.