The right answer for the question that is being asked and shown above is that: "D.(x – 15)2 + 94." The function f(x) = x2 + 22x + 58 is translated 4 units to the right and 16 units up. the vertex form of the new function is that D.(x – 15)2 + 94<span>
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I will interpret and evaluate your expression following order of operations rules strictly. 6*5 (multiplication) and 3*3*3 / 3 (division) must be done first, before subtraction. Then we have 30 - 9, or 21. If you truly meant 3*3*3, why not write that as 3^3?
A) 26
——
3
b) 26
Hope this helps
![2(x-5)-7x\lt-25](https://tex.z-dn.net/?f=2%28x-5%29-7x%5Clt-25)
![2x-10-7x\lt-25](https://tex.z-dn.net/?f=2x-10-7x%5Clt-25)
(div both sides by -5 and flip the inequality sign)
![x\gt3](https://tex.z-dn.net/?f=x%5Cgt3)
The answer is C.
Hope this helps :)
Answer:
<h2>3240 it's not a perfect cube.</h2><h2>The smallest number should 3240 be multiplied so that the product is a perfect cube is 15² = 225.</h2>
Step-by-step explanation:
3240 is a perfect cube if 3240 = n³ (n ∈ N).
Use the Prime Factorization:
![\begin{array}{c|c}3240&2\\1620&2\\810&2\\405&5\\81&3\\27&3\\9&3\\3&3\\1\end{array}\\\\3240=2\cdot2\cdot2\cdot5\cdot3\cdot3\cdot3\cdot3=2^3\cdot3^3\cdot5\cdot3=(2\cdot3)^3\cdot5\cdot3=6^3\cdot5\cdot3](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7Cc%7D3240%262%5C%5C1620%262%5C%5C810%262%5C%5C405%265%5C%5C81%263%5C%5C27%263%5C%5C9%263%5C%5C3%263%5C%5C1%5Cend%7Barray%7D%5C%5C%5C%5C3240%3D2%5Ccdot2%5Ccdot2%5Ccdot5%5Ccdot3%5Ccdot3%5Ccdot3%5Ccdot3%3D2%5E3%5Ccdot3%5E3%5Ccdot5%5Ccdot3%3D%282%5Ccdot3%29%5E3%5Ccdot5%5Ccdot3%3D6%5E3%5Ccdot5%5Ccdot3)
![3240=6^3\cdot15\qquad\text{multiply both sides by}\ 15^2\\\\3240\cdot15^2=6^3\cdot15^3=3240\cdot15^2=(6\cdot15)^3=90^3](https://tex.z-dn.net/?f=3240%3D6%5E3%5Ccdot15%5Cqquad%5Ctext%7Bmultiply%20both%20sides%20by%7D%5C%2015%5E2%5C%5C%5C%5C3240%5Ccdot15%5E2%3D6%5E3%5Ccdot15%5E3%3D3240%5Ccdot15%5E2%3D%286%5Ccdot15%29%5E3%3D90%5E3)
Used:
![a^n\cdot a^m=a^{n+m}\\\\(ab)^n=a^nb^m](https://tex.z-dn.net/?f=a%5En%5Ccdot%20a%5Em%3Da%5E%7Bn%2Bm%7D%5C%5C%5C%5C%28ab%29%5En%3Da%5Enb%5Em)