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kicyunya [14]
3 years ago
14

6x5-3x3x3 divide by 3

Mathematics
2 answers:
Talja [164]3 years ago
7 0

I will interpret and evaluate your expression following order of operations rules strictly.  6*5 (multiplication) and 3*3*3 / 3 (division) must be done first, before subtraction.  Then we have 30 - 9, or 21.  If you truly meant 3*3*3, why not write that as 3^3?

Papessa [141]3 years ago
7 0
i think it is 90 idk i tried
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Given the parent function f(x)=x^2 describe the graph of y=(0.2x)^2
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We have the following function:
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Triangle ABC has vertices at (-3, -1), (-1, 2) and (6, 1). What is the perimeter of triangle ABC, rounded to the nearest tenth?
Marta_Voda [28]

Perimeter=19.9units

Why?

We can find the perimeter of any triangle adding the length of its sides. Since we are given 3 points, we need to calculate the length of the three sides of the triangle,  and then add them to know the perimeter of the triangle.

Let be the points:

A(-3,-1)

B(-1,2)

C(6,1)

<h3>- Distances</h3>

From A to B:

d(A,B)=\sqrt{(-1-(-3))^{2}+(2-(-1)^{2}}\\\\d(A,B)=\sqrt{(2)^{2}+(3)^{2}}=\sqrt{4+9}=3.61units

From A to C:

d(A,C)=\sqrt{6-(-3))^{2}+(1-(-1)^{2}}\\\\d(A,B)=\sqrt{(9)^{2}+(2)^{2}}=\sqrt{81+4}=9.22units

From B to C:

d(B,C)=\sqrt{6-(-1))^{2}+(1-2)^{2}}\\\\d(A,B)=\sqrt{(7)^{2}+(-1)^{2}}=\sqrt{49+1}=7.07units

Now, calculating the perimeter, we have:

Perimeter=d(A,B)+d(A,C)+d(B,C)=3.61units+9.22units+7.07units\\\\Perimeter=19.9units

Have a nice day!

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