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3 years ago

14

6x5-3x3x3 divide by 3

2 answers:

Talja [164]3 years ago

7 0

I will interpret and evaluate your expression following order of operations rules strictly. 6*5 (multiplication) and 3*3*3 / 3 (division) must be done first, before subtraction. Then we have 30 - 9, or 21. If you truly meant 3*3*3, why not write that as 3^3?

Papessa [141]3 years ago

7 0

i think it is 90 idk i tried

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Mason says that (12x + 4) - (-3x + 5) and 15x - 1 are equivalent. Is he correct? Explain

julia-pushkina [17]

Answer:

Yes

Step-by-step explanation:

12x minus -3x is the same as adding two positives. That gives us 15x. 4 - 5 is -1. Putting the two simplified parts of the expression together, we get 15x - 1. Mason is correct.

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3 years ago

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mr_godi [17]

Hey there Jnorman1287.

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3 years ago

Match each series with the equivalent series written in sigma notation

PIT_PIT [208]

Answer:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

$3 + 12 + 48 + 192 + 768$

The expression can be written as:

$3 \to 3*4^{0$ --- 0

$12 \to 3 * 4^{1$ ---- 1

$48 \to 3 * 4^{2$ --- 2

$192 \to 3 * 4^{3$ ---- 3

$768 \to 3 * 4^{4$ ---- 4

For the nth term, the expression is:

$Term = 3 * 4^{n$ ---- n

So, the summation is:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

Solving (b):

$4 + 32 + 256 + 2048 + 16384$

The expression can be written as:

$4 \to 4 * 8^0$ --- 0

$32 \to 4 * 8^1$ ---- 1

$256 \to 4 * 8^2$ --- 2

$2048 \to 4 * 8^3$ ---- 3

$16384 \to 4 * 8^4$ ---- 4

For the nth term, the expression is:

$Term \to 4 * 8^n$ ---- n

So, the summation is:

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

Solving (c):

$2 + 6 + 18 + 54 + 162$

The expression can be written as:

$2 \to 2 * 3^0$ --- 0

$6 \to 2 * 3^1$ ---- 1

$18 \to 2 * 3^2$ --- 2

$54 \to 2 * 3^3$ ---- 3

$162 \to 2 * 3^4$ ---- 4

For the nth term, the expression is:

$Term \to 2 * 3^n$ ---- n

So, the summation is:

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

Solving (d):

$3 + 15 + 75 + 375 + 1875$

The expression can be written as:

$3 \to 3 * 5^0$ --- 0

$15 \to 3 * 5^1$ ---- 1

$75 \to 3 * 5^2$ --- 2

$375 \to 3 * 5^3$ ---- 3

$1875 \to 3 * 5^4$ ---- 4

For the nth term, the expression is:

$Term \to 3 * 5^n$ ---- n

So, the summation is:

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

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2 years ago

I would love some help pls, if anyone could talk me through it, that would be phenomenal I have no clue what’s going on lol

maks197457 [2]

Answer:

B) 7x - 3 = 4

Step-by-step explanation:

3x - 12 = -9

3x = 3

x = 1

A) NOPE

x - 5 = -6

x = -1

B) YES

7x - 3 = 4

7x = 7

x = 1

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3 years ago

Two or more equations that have the same solution set called ________ equations

masya89 [10]

Equivalent system, equivalent systema of equations

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2 years ago

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