6x5-3x3x3 divide by 3

2 answers:

7 0

I will interpret and evaluate your expression following order of operations rules strictly. 6*5 (multiplication) and 3*3*3 / 3 (division) must be done first, before subtraction. Then we have 30 - 9, or 21. If you truly meant 3*3*3, why not write that as 3^3?

Papessa [141]3 years ago

7 0

i think it is 90 idk i tried

You might be interested in

9. Determine whether or not the number 257 is prime.

Sladkaya [172]

Answer:

257 is prime.

Step-by-step explanation:

To evaluate if a number is prime, we just need to evaluate it for the prime numbers that are equal or lesser than the said number's square root.

In this case, √257 = 16.03 so we just need to see if 257 is divisible by <u>2, 3, 5, 7, 11 and 13</u> (the prime numbers that come before 16)

257 is odd, so it is not divisible by 2.

The sum of its digits is 14, therefore, it is not divisible by 3.

257 ends in 7, therefore it's not divisible by 5.

257/ 7 = 36.71 so it's not divisible by 7.

257/ 11 = 23.36 so it's not divisible by 11

Finally 257 / 13= 19.76 so it's not divisible by 13.

Therefore, 257 is prime.

7 0

2 years ago

Let G denote the centroid of triangle ABC. If triangle ABG is equilateral with side length 2, then determine the perimeter of tr

zhannawk [14.2K]

We know from Euclidean Geometry and the properties of a centroid that GC=2GM. Now GM=sin60*GA= $\sqrt{3}$ . Hence CM=GC+GM=3* $\sqrt{3} /$ . Now, since GM is normal to AB, we have by the pythagoeran theorem that:
$AC^2=AM^2+GM^2=BM^2+GM^2=BC^2$
Hence, we calculate from this that AC^2= 28, hence AC=2* $\sqrt{7}$ =BC. Thus, the perimeter of the triangle is 2+4* $\sqrt{7}$ .