What shows the volume
1 answer:
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Explanation:
<u><em>First you subtract by -1 both sides of an equation.</em></u>
<u><em></em></u>
<u><em>Then, simplify the number.</em></u>
<u><em>34-1=33</em></u>
<u><em>x>33</em></u>
<u><em>Or interval notation 33,∞ </em></u>
<u><em>Final answer: → x>33 and 33,∞</em></u>
<u><em>Hope this helps!</em></u>
<u><em>Thanks!</em></u>
So the function is
the intial value is where x=0
where x=0, the value of f(0)=3
grouth is 1/3 but it is decay, so it might be correct, or not because it is decay
it is exponential decay
true it is a stretch of the funciton f(x)=(1/3)^x
when x=3, then f(3)=1/9
the true things are
The function shows exponential decay.
The function is a stretch of the function f(x) = (1/3)x .
the intial value is where x=0
where x=0, the value of f(0)=3
grouth is 1/3 but it is decay, so it might be correct, or not because it is decay
it is exponential decay
true it is a stretch of the funciton f(x)=(1/3)^x
when x=3, then f(3)=1/9
the true things are
The function shows exponential decay.
The function is a stretch of the function f(x) = (1/3)x .