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Scorpion4ik [409]
3 years ago
10

20 POINTS HURRY QUICK WILL GIVE BRAINLIEST

Mathematics
1 answer:
Mamont248 [21]3 years ago
4 0

Answer:

A function is a rule that takes an input, does something to it,

and gives a unique corresponding output.

There is a special notation, called "function notation," that is used to represent this situation:

if the function name is  f , and the input name is  x ,

Step-by-step explanation:

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Determine which postulate can be used to prove that the triangles are congruent. If it is not possible to prove congruence, writ
irakobra [83]

Answer:

The triangles are congruent by

SSS

Step-by-step explanation:

Given:

First Label the Diagram:

AB ≅ CD

AD ≅ BC

To Prove:

Δ ABC ≅ Δ CDA

Proof:

In  Δ ABC and Δ CDA

AB ≅ CD     ....……….{Given}

BC ≅ DA     …………..{Given}

AC ≅ AC     ……….{Reflexive Property}

Δ ABC ≅ Δ CDA  ….{ By Side-Side-Side test}

8 0
3 years ago
C- 14b=<br><br> if c equals -7 and b equals 1/7
Andrew [12]
-7 -14(1/7)

remove parenthesis

14 * 1/7 = 2  (14/1 * 1/7 = 2/1 which we reduce to just 2)

-7 -2

-9
8 0
2 years ago
Solve for y. Please help!!
Nadya [2.5K]

Answer:

y=3\sqrt{7}\ units

Step-by-step explanation:

see the attached figure with letters to better understand the problem

we know that

In the right triangle ABD

tan(

In the right triangle BCD

tan(

remember that

m< BAD=m<CBD

therefore

tan(

equate the equations

y/9=7/y

y^{2}=63

y=3\sqrt{7}\ units

7 0
3 years ago
(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?
DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500

  • There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111

  • There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611

7 0
3 years ago
What are the prime fractorization of 240?
frozen [14]

Answer:

The prime factorization of 240, with exponents, is 24 × 3 × 5.

8 0
3 years ago
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