Answer:
-11, -10, -9
Step-by-step explanation:
The middle one is their average, -30/3 = -10. The three integers are -11, -10, -9.
_____
I like to work "consecutive integer" problems using the average value of the integers involved. The average of <u>two</u> consecutive integers is 1/2 more than the small one, and 1/2 less than the large one, for example. Here, there are <u>three</u> consecutive integers, so their average is the middle one.
If you want to write that using an equation, you can let x represent the middle integer. Then the sum is ...
(x -1) +(x) + (x+1) = 3x = -30
x = -30/3 = -10 . . . . . the same average we computed above.
x -1 = -11 . . . . . the smaller of the other two integers
x +1 = -9 . . . . . the larger of the other two integers
Step-by-step explanation:
First, standard form is
a
x
+
b
y
+
c
=
0
In this question, we can expend the formula and rearrange it.
You can try it first, and the steps are as follow:
Step 1: Expend it
2
y
+
3
=
−
1
3
x
+
2
3
As there are fraction in the formula and it doesn't look good, we can eliminate it by multiplyng 3.
Step 2: Multiply by 3
6
y
+
9
=
−
1
x
+
2
Step 3: Rearrange the terms
x
+
6
y
+
7
=
0
1. 11x+9=-7
-9 -9
11x=-16
/11 /11
x= -16/11
2. 2x-8-6x=90
2x-6x=-4x
-4x-8=90
+8 +8
-4x=98
/-4 /-4
x=-24.5
3. 5(3x-4)=x+6+12x
15x-20=13x+6
-13x. -13x
2x-20=6
+20. +20
2x=26
/2. /2
x=13
Is it asking how many she began with before she sold them? If so, then I think at the beginning she started out with 40. I think she had 40 because she sold half, and when you divide 40 by 2 it divides perfectly giving you 20. Then add 16 to that and you come out with 36.