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3 years ago

Rewrite the equation by completing the square.

Mathematics

1 answer:

ser-zykov [4K]3 years ago

4 0

Answer:

4 × 2 + 20×

Step-by-step explanation:

please your questions are mixed up

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Let f(x) = x^3-3x^2+2 and g(x) = x^2 -6x+11 Enter the value of x such that f(x)=g(x)

Licemer1 [7]

The value of x such that f(x) = g(x) is x = 3

<h3>Quadratic equation</h3>

Given the following expressions as shown

f(x) = x^3-3x^2+2 and;

g(x) = x^2 -6x+11

Equate the expressions

x^3-3x^2+2 = x^2 -6x+11

Equate to zero

x^3-3x^2-x^2+2-11 = 0

x^3-3x^2-x^2 + 6x - 9 = 0

x^3-4x^2+6x-9 = 0

Factorize

On factorizing the value of x = 3

Hence the value of x such that f(x) = g(x) is x = 3

Learn more on polynomial here: brainly.com/question/2833285

#SPJ1

7 0

1 year ago

Which graph represents the sequence: 80, -40, 20

ANEK [815]

<span> 80/-40=-40/20=-2,
the sequence: 80, -40, 20 is a geometric sequence
its general formula is Vn+1 = q Vn, where q= -2,
if we put </span>Vn+1 = f(x)
<span> Vn = x

so we have f(x)= -2x so the graph that represents the sequence is graph of linear equation

</span>

8 0

3 years ago

Kathy is fencing in her yard that has an area of 800 square feet. Her yard is in the shape of a rectangle where the length is 60

anygoal [31]

Answer:

The dimensions of the yard are W=20ft and L=40ft.

Step-by-step explanation:

Let be:

W: width of the yard.

L:length.

Now, we can write the equation of that relates length and width:

$L=5W-60$ (Equation #1)

The area of the yard can be expressed as (using equation #1 into #2):

$Area=W*L=W*(5W-60)$ (Equation #2)

Since the Area of the yard is $800 ft^2$ , then equation #2 turns into:

$800=W*(5W-60)$

Now, we rearrange this equation:

$800=W*(5W-60)//800=5W^2-60W//5W^2-60W-800=0$

We can divide the equation by 5 :

$W^2-12W-160=0$

We need to find the solution for this quadratic. Let's find the factors of 160 that multiplied yields -160 and added yields -12. Let's choose -20 and 8, since $(-20)*8=160$ and $-20+8=-12$ . The equation factorised looks like this:

$(W-20)(W+8)=0$

Therefore the possible solutions are W=20 and W=-8. We discard W=-8 since width must be a positive number. To find the length, we substitute the value of W in equation #1:

$5*20-60=40$

Therefore, the dimensions of the yard are W=20ft and L=40ft.

7 0

2 years ago

A parabola has a vertex at the origin. The focus of the parabola is located at (–2,0).

12345 [234]

dam what Answer:

Step-by-step explanation:dom

no it’s not working

5 0

2 years ago

Machine A produces bolts at a uniform rate of 120 every 40 seconds, and Machine B produces bolts at a uniform rate of 100 every

Nutka1998 [239]

Answer:

25 seconds

Step-by-step explanation:

Hi there!

In order to answer this question, first we need to know how many bolts per second are produced by each machine, this can be known by dividing the number of bolts by the time it takes.

For machine A:

$A = \frac{120 bolts}{40 s}= 3 \frac{bolts}{s}$

For machine B:

$B = \frac{100 bolts}{20 s}= 5 \frac{bolts}{s}$

So, if the two machines run simultaneously, we will have a rate of prodcution of bolts equal to the sum of both:

$A+B=(3+5)\frac{bolts}{s}=8\frac{bolts}{s}$

Now, we need to know how much time it will take to producee 200 bolts, to find this out we need to divide the amount of bolts by the production rate:

$t = \frac{bolts}{ProductionRate}= \frac{200 bolts}{8 \frac{bolts}{s} }$

The <em>bolts</em> unit cancell each other and we are left with <em>seconds</em>

$t = \frac{200}{8} s = 25 s$

So it will take 25 seconds to produce 200 bolts with machine A and B running simultaneously.

Greetings!

4 0

3 years ago

Read 2 more answers