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stellarik [79]
2 years ago
11

An event has a 35% chance of occurring. What is the probability that the event will NOT occur?

Mathematics
2 answers:
sashaice [31]2 years ago
5 0
65% is what it would be
joja [24]2 years ago
4 0
100%-35% so the answer would be 65% 
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The angles of a quadrilateral measure 80, 100, 100, 80 in this order what kind of quadrilateral has this shape what attributes h
Harrizon [31]

Answer:

Isosceles trapezoid

Step-by-step explanation:

-An isosceles trapezoid is also sometimes called a convex quadrilateral.

-It properties include:

  • A line of symmetry can often bisects a pair of opposite sides.
  • It has to obtuse alternating with each other after which a pair of acute angles alternate with each other i.e 80°, 80°,100°,100°
  • It has a trapezoidal shape which by definition has a two pair of parallel sides.
  • The angles on it's base or ceiling are equal hence the name Isosceles Trapezoid.

8 0
3 years ago
In which quadrant is (4,-5) located
Vinvika [58]
4 in (4,-5) implies positive x-axis.
-5 in (4,-5) implies negative y-axis.

Since x is positive and y is negative in fourth quadrant, so the answer is

QUADRANT IV (or 4th quadrant.
3 0
3 years ago
Read 2 more answers
Pls help 0.5a = 2a + 3
spayn [35]

Answer:

-2

Step-by-step explanation:

0.5a=2a+3

a=-2

PLEASE MARK BRAINLIEST

5 0
2 years ago
If m(x) =x+5/x-1 and n(x) =x-3 which function has the same domain as (m.n)(x)
Travka [436]

Answer:

Step-by-step explanation:

m (x) = (x+ 5) / (x -1)        and     n(x) = x - 3.

m(x) = \dfrac{x+5}{x-1}

Hence

m(n) = \dfrac{n+5}{n-1}

but n is a function and n = x-3. Now, replace value of n on m (n)

(m(n))= \dfrac{(x-3)+5}{(x-3)-1}

simplify it

(m\bullet n)(x) =\dfrac{x+2}{x-4}\\

since (m . n) (x)  is a fraction function, its domain will be all x such that the denominator is NOT 0. That is

x-4\ne 0\rightarrow x\ne 4

among options, only C has the same denominator with (m\bullet n)(x)

Hence their domains are the same.

4 0
3 years ago
Find the global maximum and global minimum values (if they exist) of x 2 + y 2 in the region x + y = 1. If there is no global ma
Grace [21]

Given that x+y=1, we have y=1-x, so that

f(x,y)=x^2+y^2\iff g(x)=x^2+(1-x)^2

Take the derivative and find the critical points of g:

g'(x)=2x-2(1-x)=4x-2=0\implies x=\dfrac12

Take the second derivative and evaluate it at the critical point:

g''(x)=4>0

Since g'' is positive for all x, the critical point is a minimum.

At the critical point, we get the minimum value g\left(\frac12\right)=f\left(\frac12,\frac12\right)=\frac12.

5 0
3 years ago
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