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MrRissso [65]
3 years ago
13

The beginning inventory at cost is $80,000.00 and at retail is $100,000.00. Purchases at cost are $160,000.00 and the retail val

ue is $200,000.00. Net sales are $250,000.00. The ending inventory at cost is
A. $240,000
B. $50,000.00
C. $40,000
D. $192,000
Mathematics
1 answer:
DaniilM [7]3 years ago
6 0

Cost of goods available for is equal

80000+160000=240000

Retail value is equal

100000+200000=300000


This means that the cost of goods sold is 80% (240000÷300000) and gross profit is 20%


Sales= 250000 and it's cost is equal 200000 (250000×0.8)


Ending inventory

=240000-200000=40000...answer


Hope it helps!



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\large \bigstar \frak{ } \large\underline{\sf{Solution-}}

Consider, LHS

\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

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\begin{gathered}\boxed{\sf{  \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered}  \\  \\  \text{So, using this identity, we get} \\  \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

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\begin{gathered}\boxed{\sf{  \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered}  \\

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\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

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\rule{190pt}{2pt}

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