In AKLM, the measure of ZM=90°, the measure of ZL=76°, and LM = 99 feet. Find

Consider a computer that uses 6 bits to represent integers: 1 bit for the sign and 5 bits for the actual number. What's the larg

ycow [4]

Answer:

31

Step-by-step explanation:

Therefore, range of 5 bit unsigned binary number is from 0 to (25-1) which is equal from minimum value 0 (i.e., 00000) to maximum value 31 (i.e., 11111).

5 0

3 years ago

PLEASE HELP IVE BEEN STUCK FOR HOURS!

kirza4 [7]

13
14=2•7
15=3•5
16=2•2•2•2
17
18=2•3•3
19
20=2•2•5
...

5 0

3 years ago

Maddie converts z = 8(cos(300°) + isin(300°)) into rectangular form z = a + bi and determines that a = 4 and b = 4 StartRoot 3 E

Anastaziya [24]

Answer:

Option C) The value of a is correct, but the value of b is incorrect.

Step-by-step explanation:

z = 8(cos(300°) + isin(300°))

z = 8cos(300°) + 8isin(300°)

$z = 4 + i(-4\sqrt{3})\\z=4-i(4\sqrt{3} )\\$

So we can see that a = 4 which is correct but b = $-4\sqrt{3}$ and b in the question says it is b $4\sqrt{3}$ so its incorrect so Option C is your answer.

8 0

2 years ago

Read 2 more answers

The length of a rectangle is 5 yd less than twice the width, and the area of the rectangle is 52 yd^2. Find the dimensions of th

Softa [21]

Answer:

the length is 8 and the width is 6.5

Step-by-step explanation:

6.5 x 2 = 13 - 5 = 8 x 6 = 52

The Calculator can confirm.

3 0

3 years ago

Community college students conduct a survey at their college. They ask "Do you plan to transfer to a university to pursue a bacc

Tamiku [17]

Answer:

$0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697$

$0.8 + 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.903$

The 99% confidence interval would be given by (0.697;0.903)

And the best option is : 0.697 to 0.903

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

For this case the conditions we have the conditions to assume a normal distribution for the population proportion since:

np=100*0.8=80 >10 , n(1-p) = 10*(1-0.8) =20 >10

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by: