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CaHeK987 [17]
3 years ago
11

PLZ HELP!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
bezimeni [28]3 years ago
8 0

Answer:

If soccer balls are sold for $2.05 or $14.61 each, the store will break even but will not make a profit.

Inessa05 [86]3 years ago
4 0

Answer:

D.) If soccer balls are sold for $2.05 or $14.61 each, the store will break even but will not make a profit.

Step-by-step explanation:

Let us assume x = selling price of each soccer ball

y = daily profit earned from selling of soccer balls

Given that

Y= -6x^2+100x-180

where,

a = -6

b = 100

c = -180

Now we have to applied the formula which is as follows

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

= \frac{-100\pm\sqrt{100^2-4\times -6\times -180}}{2\times -6}$

= \frac{-100\pm\sqrt{10,000 - 4,320}}{-12}$

= \frac{-100\pm\sqrt{5.680}}{-12}$

= \frac{-100 + 75.3658}{-12}$

= \frac{24.6342}{-12}

x^1 = -2.05285

Now

x^2  = \frac{-100 - 75.3658}{-12}$

= \frac{- 175.3658}{-12}

x^2 = 14.6138

Based on this the option D is most appropriate as per the given situation

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a boy is standing on a pole of height 14.7m throws a stone upwards. it moves in a vertical line slightly away from the pole and
fomenos

Answer:

The time taken for the upward motion is 1 second. The same time is taken for the downward motion

It reaches a maximum height of 4.9 meters.

Step-by-step explanation:

The equation of motion is:

x(t) = -4.9t^{2} + 9.8t

Since the term which multiplies t squared is negative, the graph is concave down, that is, x increases until the vertex, where it reaches it's maximum height, then it decreases.

Vertex of a quadratic equation:

Quadratic equation in the format x(t) = at^{2} + bt + c

The vertex is the point (t_{v}, x(t_{v})), in which

t_{v} = -\frac{b}{2a}

In this question:

x(t) = -4.9t^{2} + 9.8t

So a = -4.9, b = 9.8

Vertex:

t_{v} = -\frac{9.8}{2*(-4.9)} = 1

The time taken for the upward motion is 1 second.

x(t_{v}) = x(1) = 9.8*1 - 4.9*(1)^{2} = 4.9

It reaches a maximum height of 4.9 meters.

Downward motion:

From the vertex to the ground.

The ground is t when x = 0. So

-4.9t^{2} + 9.8t = 0

4.9t^{2} - 9.8t = 0

4.9t(t - 2) = 0

4.9t = 0

t = 0

Or

t - 2 = 0

t = 2

It reaches the ground when t = 2 seconds.

The downward motion started at the vertex, when t = 1.

So the duration of the downward motion is 2 - 1 = 1 second.

5 0
3 years ago
Answer for the square root(5x-9)+1=x
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\bf \sqrt{5x-9}+1=x\implies \sqrt{5x-9}=x-1\implies 5x-9 = (x-1)^2 \\\\\\ 5x-9=\stackrel{\mathbb{FOIL}}{x^2-2x+1}\implies 5x=x^2-2x+10\implies 0=x^2-7x+10 \\\\\\ 0=(x-5)(x-2)\implies x= \begin{cases} 5\\ 2 \end{cases}

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3 years ago
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I think the answer is 40
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