Question

Find four consecutive integers with the sum of -142

Answer 1

n, n + 1, n + 2, n + 3 - four consecutive integers

-142 - the sum

The equation:

n + (n + 1) + (n + 2) + (n + 3) = -142

n + n + 1 + n + 2 + n + 3 = -142

4n + 6 = -142     |subtract 6 from both sides

4n = -148    |divide both sides by 4

n = -37

n + 1 = -37 + 1 = -36

n + 2 = -37 + 2 = -35

n + 3 = -37 + 3 = -34

Answer: -37, -36, -35, -34.