n, n + 1, n + 2, n + 3 - four consecutive integers
-142 - the sum
The equation:
n + (n + 1) + (n + 2) + (n + 3) = -142
n + n + 1 + n + 2 + n + 3 = -142
4n + 6 = -142 |subtract 6 from both sides
4n = -148 |divide both sides by 4
n = -37
n + 1 = -37 + 1 = -36
n + 2 = -37 + 2 = -35
n + 3 = -37 + 3 = -34
Answer: -37, -36, -35, -34.
