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3 years ago

Find four consecutive integers with the sum of -142

Mathematics

1 answer:

Akimi4 [234]3 years ago

5 0

n, n + 1, n + 2, n + 3 - four consecutive integers

-142 - the sum

The equation:

n + (n + 1) + (n + 2) + (n + 3) = -142

n + n + 1 + n + 2 + n + 3 = -142

4n + 6 = -142 |subtract 6 from both sides

4n = -148 |divide both sides by 4

n = -37

n + 1 = -37 + 1 = -36

n + 2 = -37 + 2 = -35

n + 3 = -37 + 3 = -34

Answer: -37, -36, -35, -34.

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2 years ago

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<h3>Given information-</h3>

The triangle for the given problem is shown in the image below.

Form the figure the length of the each side is $16 \sqrt{3}$ units.

As all the sides are equal thus the $\Delta MNO$ is a equilateral triangle in which the height of the divides the triangle into two equal part of the length $8\sqrt{3}$ at point <em>R.</em>

<h3>Height of the triangle-</h3>

Height of the triangle is the altitude of the triangle and which is drawn perpendicular from the vertex of the triangle to the opposite side.

Now in the $\Delta MRN$ , the length of the hypotenuse is $16 \sqrt{3}$ units and the length of the base is $8\sqrt{3}$ units. Let <em>h </em>is the height of the triangle thus by the Pythagoras theorem,

$(16\sqrt{3})^2 =(8\sqrt{3})^2+h^2$

Solve for <em>h,</em>

<em />

<em /> $\begin{aligned}h^2 &=(16\sqrt{3})^2 -(8\sqrt{3})^2\\h^2 &=16\times16\times3 -8\times8\times3\\h^2 &=576\\h &=\sqrt{576}\\h &=24\\\end$ <em />

<em />

Thus the height of the tringle is 24 units. Hence option 2 is the correct option.

Learn more about the equilateral triangle here;

brainly.com/question/4268382

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2 years ago

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