Answer:
42.69% of information is acquired by the student in two weeks.
Step-by-step explanation:
We are given the following in the question:

where a and b are constants.

p tells us about the percentage of acquired knowledge that a person retains after t weeks.
We have to find the percentage of knowledge acquired in two week.
We put t = 2

Thus, 42.69% of information is acquired by the student in two weeks.
Answer:
a) The percentage of athletes whose GPA more than 1.665 is 87.49%.
b) John's GPA is 3.645.
Step-by-step explanation:
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

a)Find the percentage of athletes whose GPA more than 1.665.
This is 1 subtracted by the pvalue of Z when X = 1.665. So



has a pvalue of 0.1251
1 - 0.1251 = 0.8749
The percentage of athletes whose GPA more than 1.665 is 87.49%.
b) John's GPA is more than 85.31 percent of the athletes in the study. Compute his GPA.
His GPA is X when Z has a pvalue of 0.8531. So it is X when Z = 1.05.




John's GPA is 3.645.
Answer:
x=16
y=-6
Step-by-step explanation:
If you look at the picture, you set it up as part over whole is equal to percent over 100. then you just multiply across.