Equation for perimeter is 2L +2W
perimeter of the lot is 390 ft
so we have 390 = 2L +2w
divide all terms by 2:
195 = L + W
rewrite this as L = 195-W ( eq.1)
cost of fence for the length = 36 per foot so we have 36L
cost of fence for width = 6 per foot so we have 6W
the fence was 1 length and 2 sides
so we have 36l + 6w +6w = total cost
total cost is 4980
so we have 4980 = 36L + 6w +6w
combine like terms:
4980 = 36L +12w
replace L with eq1 from above:
4980 = 36(195-w) +12w
distribute:
4980 = 7020 -36w +12w
combine like terms:
4980 = 7020-24w
subtract 7020 from both sides:
-2040 = -24w
divide both sides by -24:
-2040 / -24 = 85
width = 85 feet
using eq1 L = 195 - 85
Length = 110 feet
lond = 110 feet
short = 85 feet
For the squirrel questions
1.c
2.b
3.d
4.a
There are 2 answers one of them is 1/4 and the other is 25/100 they are both the same and if the answer is in decimals it would be 0.25
Answer: The radius of circle is 19.1 meters.
Explanation:
Since we have given that
Circumference of a circle = 120 meters
As we know the formula for "Circumference of circle" i.e.
Hence, the radius of circle is 19.1 meters.
Answer:
The first x = 4
The second x = 6.25
Step-by-step explanation:
For the first question. We need to make use of the midsegment theorem which says, if you have a trapezoid with base1 and base2, then the midsegment is given as:
(Base1 + Base 2)/2.
We are given Base 1 = 5x + 3 and Base 2 = 12x – 3 and the midsegment, JK = 34. To find x we have:
(5x + 3 + 12x – 3)/2 = 34
This gives: 17x/2 = 34.
Therefore, x = (34 x 2)/17 = 4. Thus, x = 4.
As for the second question, we have two diagonals of the rectangle, FH and JG. We are given that JG = 40. We know that the diagonals of the rectangle are equal, therefore FH = 40 as well.
We are told that M is the midpoint, meaning FM is half of the diagonal FH. Mathematically this can be written as:
FM = FH/2
Given that FM = 3.2x and FH = 40, we have:
3.2x = 40/2
3.2x = 20
x = 20/3.2
x = 6.25
