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Irina18 [472]
3 years ago
7

Identify the two events described in the study and determine if the results indicate that the events are independent or dependen

t. Explain your reasoning. A study found that there is no relationship between being around cigarette smokers and developing heart disease. Identify the two events. Choose the correct answer below O A. Being around people with heart disease and exposure to cigarette smokers 0 B. Being around cigarette smokers and developing heart disease ° C. Being around cigarette smokers and not being around cigarette smokers. 0 D. Developing heart disease and not developing heart disease. Are the events independent or dependent? 0 A. Dependent. Being around cigarette smokers does cause heart disease. O B. Independent. Developing heart disease is related to being around cigarette smokers. C. Independent. Being around cigarette smokers does not cause heart disease. D. Dependent. The type of heart disease developed is caused by one's exposure to cigarette smokers.
Mathematics
1 answer:
Monica [59]3 years ago
4 0

Answer:  B. Being around cigarette smokers and developing heart disease .

C. Independent. Being around cigarette smokers does not cause heart disease.

Step-by-step explanation:

Given : A study found that there is no relationship between being around cigarette smokers and developing heart disease.

i.e. The two events here are Being around cigarette smokers and developing heart disease .

Since there is no relationship between the above two events.

Being around cigarette smokers does not cause heart disease.

It means that the two events are not dependent on each other i.e. they are independent.

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likoan [24]

Answer:

for question 13

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Step-by-step explanation:

for 14

    x. 150

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    z. 150

i cant say that this is totally correct but im taking a educated guess

7 0
2 years ago
Read 2 more answers
The realtor and her clients do not know the average home sale price for all of Guelph (500 was actually just a guess). However,
strojnjashka [21]

Answer:

a) The 99% confidence interval would be given by (346.708;453.292)

b) The 99% confidence interval would be given by (338.445;461.555)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=400 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=80 represent the population standard deviation

n=15 represent the sample size  

2) Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58

Now we have everything in order to replace into formula (1):

400-2.58\frac{80}{\sqrt{15}}=346.708    

400+2.58\frac{80}{\sqrt{15}}=453.292

So on this case the 99% confidence interval would be given by (346.708;453.292)    

3) Part b

For this case we don't know the population deviation so we need to use the t distribution instead the normal standard distribution.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

We need to find the degrees of freedom first df=n-1=15-1=14

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,14)".And we see that t_{\alpha/2}=2.98

Now we have everything in order to replace into formula (1):

400-2.98\frac{80}{\sqrt{15}}=338.445    

400+2.98\frac{80}{\sqrt{15}}=461.555

So on this case the 99% confidence interval would be given by (338.445;461.555)    

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Mars2501 [29]

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TiliK225 [7]

<em>Answer below:</em>



<em>Hope this helps :-)</em>

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OlgaM077 [116]

Answer:

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Step-by-step explanation:

it is simply the sum of home credit which is

=3000 + 1600

=4600

5 0
3 years ago
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