Answer:
The mass of the silver block is 95.52 grams.
Explanation:
Heat lost by silver will be equal to heat gained by the water
![-Q_1=Q_2](https://tex.z-dn.net/?f=-Q_1%3DQ_2)
Mass of silver= ![m_1](https://tex.z-dn.net/?f=m_1)
Specific heat capacity of silver = ![c_1=0.235 J/g^oC](https://tex.z-dn.net/?f=c_1%3D0.235%20J%2Fg%5EoC%20)
Initial temperature of the silver = ![T_1=58.4^oC](https://tex.z-dn.net/?f=T_1%3D58.4%5EoC)
Final temperature of a silver =
=
![Q_1=m_1c_1\times (T-T_1)](https://tex.z-dn.net/?f=Q_1%3Dm_1c_1%5Ctimes%20%28T-T_1%29)
Mass of water= ![m_1=100.0 g](https://tex.z-dn.net/?f=m_1%3D100.0%20g)
Specific heat capacity of water= ![c_2=4.186 J/g^oC](https://tex.z-dn.net/?f=c_2%3D4.186%20J%2Fg%5EoC%20)
Initial temperature of the water = ![T_3=25^oC](https://tex.z-dn.net/?f=T_3%3D25%5EoC)
Final temperature of water = ![T_3=T=26.7^oC](https://tex.z-dn.net/?f=T_3%3DT%3D26.7%5EoC)
![Q_2=m_2c_2\times (T-T_3)](https://tex.z-dn.net/?f=Q_2%3Dm_2c_2%5Ctimes%20%28T-T_3%29)
![-Q_1=Q_2](https://tex.z-dn.net/?f=-Q_1%3DQ_2)
![-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)](https://tex.z-dn.net/?f=-%28m_1c_1%5Ctimes%20%28T-T_1%29%29%3Dm_2c_2%5Ctimes%20%28T-T_3%29)
![-(m_1\times 0.235 J/g^oC\times (26.7^oC-58.4^oC))=100.0 g\times 4.186 J/g^oC\times (26.7^oC-25.0^oC)](https://tex.z-dn.net/?f=-%28m_1%5Ctimes%200.235%20J%2Fg%5EoC%5Ctimes%20%2826.7%5EoC-58.4%5EoC%29%29%3D100.0%20g%5Ctimes%204.186%20J%2Fg%5EoC%5Ctimes%20%2826.7%5EoC-25.0%5EoC%29)
On substituting all values:
we get, ![m_1 = 95.52 g](https://tex.z-dn.net/?f=m_1%20%3D%2095.52%20g)
The mass of the silver block is 95.52 grams.
Answer:
Active transport
Explanation:
Sodium-potassium pumps are examples of Active type of cellular transport. Sodium potassium pump exchanges sodium ions from potassium ions through the plasma membrane of animal cells.
Whereas Active transport can be defined as movement of ions and molecules across a cell membrane to the region of higher concentration with the help of enzymes and energy.
Answer:
Manganese (II) Phosphate
Explanation:
Mn3(PO4)2 is the compound given in this question. Manganese is the metal and hence it will come first in the name. Along with the name of metal it is essential to determine the valency of the metals based on the compound structure.
Here 2 PO4 attaches with 3 Mn
Valence of PO4 is -3
So the total electrons contributed by PO4 is 3*2 = 6
Now Mn has 3 atoms in the compound. Thus, per atom the valency must be 2 in order to satisfy -6 charge of PO4
Thus, valency of Mn is 2
So, the name will be
Manganese (II) Phosphate.
Answer:
![Q=330J](https://tex.z-dn.net/?f=Q%3D330J)
Explanation:
Hello!
In this case, since the energy involved during a heating process is calculated as shown below:
![Q=mC(T_2-T_1)](https://tex.z-dn.net/?f=Q%3DmC%28T_2-T_1%29)
Whereas we consider the mass, heat capacity and temperature; we are able to plug in the given data to obtain:
![Q = 20g*1.1\frac{J}{g\°C}(40\°C-25\°C)\\\\Q = 330J](https://tex.z-dn.net/?f=Q%20%3D%2020g%2A1.1%5Cfrac%7BJ%7D%7Bg%5C%C2%B0C%7D%2840%5C%C2%B0C-25%5C%C2%B0C%29%5C%5C%5C%5CQ%20%3D%20330J)
Best regards!