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SashulF [63]
3 years ago
12

C₇H₉+ HNO₃ → C₇H₆(NO₂)₃+ H₂O Balance the formula

Chemistry
1 answer:
Ulleksa [173]3 years ago
3 0

Hey there!

C₇H₉+ HNO₃ → C₇H₆(NO₂)₃+ H₂O

Our elements: C, H, N, and O.

Balance H.

Ten on the left, eight on the right. Add a coefficient of 2 in front of H₂O.

C₇H₉+ HNO₃ → C₇H₆(NO₂)₃+ 2H₂O

Balance N.

One on the left, three on the right. Add a coefficient of 3 in front of HNO₃.

C₇H₉+ 3HNO₃ → C₇H₆(NO₂)₃+ 2H₂O

This unbalanced H, let's increase the coefficient in front of H₂O from 2 to 3 to rebalance.

C₇H₉+ 3HNO₃ → C₇H₆(NO₂)₃+ 3H₂O

Balance O.

Nine on the left, nine on the right. Already balanced.

Balance C.

Seven on the left, seven on the right. Already balanced.

Our final balanced equation:

C₇H₉+ 3HNO₃ → C₇H₆(NO₂)₃+ 3H₂O

Hope this helps!

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Option B is correct.

The net ionic chemical reaction when Cu(NO₃)₂ reacts with water is

Cu²⁺(aq) + H₂O(l) ⇌ Cu(OH)¹⁺(aq) + H¹⁺(aq)

Explanation:

When ions dissolve in polar solvents (in water especially), then often attract ions of opposite signs.

Cu(NO₃)₂ dissolves into Cu²⁺ & NO₃⁻ and water contains H¹⁺ & OH⁻

The Cu²⁺ attracts the OH⁻ from water, thereby giving the Cu(OH)¹⁺ ion (with a net charge of +2-1 = +1) and the NO₃⁻ takes up the H⁺ ion.

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  • Covalent bond is formed by the sharing of electrons between two elements.
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Electronic Configuration of Group VII-A : ns^2np^5

This group require 1 electron to attain stable electronic configuration.

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So, there will be complete transfer of electron from Group VII-A to Group I-A and hence, will form ionic bond between them.

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