The greatest common factor is the product of shared primes of the numbers prime factorizations.
32=2*2*2*2*2, 80=2*2*2*2*5 So the GCF is 2*2*2*2=16
So there will be 16 teams with 2 forwards and 5 guards each.
Answer:
P(2.50 < Xbar < 2.66) = 0.046
Step-by-step explanation:
We are given that Population Mean,
= 2.58 and Standard deviation,
= 0.75
Also, a random sample (n) of 110 households is taken.
Let Xbar = sample mean household size
The z score probability distribution for sample mean is give by;
Z =
~ N(0,1)
So, probability that the sample mean household size is between 2.50 and 2.66 people = P(2.50 < Xbar < 2.66)
P(2.50 < Xbar < 2.66) = P(Xbar < 2.66) - P(Xbar
2.50)
P(Xbar < 2.66) = P(
<
) = P(Z < -1.68) = 1 - P(Z 1.68)
= 1 - 0.95352 = 0.04648
P(Xbar
2.50) = P(
) = P(Z
-3.92) = 1 - P(Z < 3.92)
= 1 - 0.99996 = 0.00004
Therefore, P(2.50 < Xbar < 2.66) = 0.04648 - 0.00004 = 0.046
Each flower arrangement will have 5 lillies and 13 roses
Answer:
1st 3rd and 4th
Step-by-step explanation:
I just did that