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Svetradugi [14.3K]
3 years ago
6

Write a fraction as a decimal 2/10

Mathematics
2 answers:
kykrilka [37]3 years ago
8 0

Answer:

0.2

Step-by-step explanation:

So, to find the decimal of this fraction, you would just divide 2 by 10. (NOT THE OTHER WAY AROUND!!!)

2÷10=0.2

Hope this helped!

podryga [215]3 years ago
3 0

The first digit in a decimal would be the tenths, then hundredths, then thousandths, and so on. so 2 tenths as a fraction can be .2 as a decimal.

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If f(x) - 3x? and g(x) = x+2, find (f•g)(x).
hammer [34]

Answer:

-3x^{2} -6x

Step-by-step explanation:

f(x)= - 3x

g(x) = x+2

(f•g)(x)

f(x) • g(x)

plug in

-3x • x+2

-3x(x+2)

distribute the -3x

-3x^{2} -6x

hope this helps!

6 0
3 years ago
Find the median of the data. <br><br> 24,74,61,29,38,27,68,54
Nataly_w [17]

Answer:

The median of the data is 46.

Step-by-step explanation:

Put the numbers in order so it would look like this.

24, 27, 29, 38, 54, 61, 68, 74

The ones in the middle would be the mean, however, there are two numbers in an even-number data, 38 and 54.

Add these two numbers together to get 92 and divide that number by 2 to get your median which is 46.

7 0
2 years ago
Read 2 more answers
Do well-rounded people get fewer colds?
asambeis [7]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if people with less social contact get more colds than people who are involved in a variety of social activities.

For this, a sample of 276 healthy men and women was taken.

n₁= 96 had few social outlets

n₂= 105 had six or more activities

These two groups were exposed to the cold virus and the following proportions of individuals that got sick were obtained:

p'₁= 0.62 (62% of the people with few social outlets got sick)

p'₂= 0.35 (35% of the people with six or more activities got sick)

The study variables are X₁: number of people with few social outlets that got sick after being exposed to the cold virus, in a sample of 96, and X₂: number of people with six or more activities that got sick after being exposed to the cold virus, in a sample of 105.

You have to construct a 99% CI for the difference these two populations since there is no specific order given I'll estimate: p₁ - p₂

(p'₁ - p'₂) ± Z_{1-\alpha /2} * \sqrt{\frac{p'_1(1-p'_1)}{n_1} +\frac{p'_2(1-p'_2)}{n_2} }

Z_{1-\alpha /2}= Z_{0.995}= 2.586

(0.62-0.35) ± 2.586 \sqrt{\frac{0.62*0.38}{96} +\frac{0.35*0.65}{105} }

[0.094; 0.045]

With a 99% confidence level, you'd expect that the difference between the proportion of people with few social outlets that got sick and the proportion of people with six or more social activities that got sick after being exposed to the cold virus.

I hope it helps!

8 0
2 years ago
The prices of five used cars are given below. Which price is an outlier to the data set? $16,250, $15,495, $12,022, $985, $12,24
Mariulka [41]

Answer:

The outlier is $985

Step-by-step explanation:

All the other numbers are very high/expensive. This number is low.

6 0
3 years ago
Read 2 more answers
Gene has a gasoline budget of $225 per month. He uses an average of $6 of gasoline each day he drives. Which of the following eq
worty [1.4K]
225 - 6x I'm not quite sure but I hop this helps
5 0
3 years ago
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