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goldenfox [79]
3 years ago
9

PLEபாப்Nச*பபபபபபபபப-பாாபோபாபாபாஇப்பகன்​

Mathematics
2 answers:
WINSTONCH [101]3 years ago
6 0
No the answer is
N = *・゜゚・*:.。..。.:*・'(*゚▽゚*)'・*:.。. .。.:*・゜゚・*
r-ruslan [8.4K]3 years ago
5 0

the answer is

போபாபாபா = Popapapa

i think....

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In an arithmetic sequence, t4 + t5 + t6 = 300, and t15 +t16+ t17 = 201. Find t18.
stiks02 [169]
In an arithmetic sequence:
Tn=t₁+(n-1)d

t₄=t₁+(4-1)d=t₁+3d
t₅=t₁+(5-1)d=t₁+4d
t₆=t₁+(6-1)d=t₁+5d

t₄+t₅+t₆=(t₁+3d) +(t₁+4d)+(t₁+5d)=3t₁+12d

Therefore:
3t₁+12d=300    (1)


t₁₅=t₁+(15-1)d=t₁+14d
t₁₆=t₁+(16-1)d=t₁+15d
t₁₇=t₁+(17-1)d=t₁+16d

t₁₅+t₁₆+t₁₇=(t₁+14d)+(t₁+15d)+(t₁+16d)=3t₁+45d

Therefore:
3t₁+45d=201    (2)

With the equations (1) and (2) we make an system of equations:

3t₁+12d=300
3t₁+45d=201

we can solve this system of equations by reduction method.

  3t₁+12d=300
-(3t₁+45d=201)
-----------------------------
       -33d=99      ⇒d=99/-33=-3

3t₁+12d=300
3t₁+12(-3)=300
3t₁-36=300
3t₁=300+36
3t₁=336
t₁=336/3
t₁=112

Threfore:

Tn=112+(n-1)(-3)
Tn=112-3n+3
Tn=115-3n

Now, we calculate T₁₈:

T₁₈=115-3(18)=115-54=61

Answer: T₁₈=61




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3 years ago
Problem page a light bulb consumes 2400 watt-hours per day. how many watt-hours does it consume in 3 days and 6 hours?
Volgvan
Calculate for 3 days: 2,400 x 3 = 7,200

Calculate 1 day per hour: 2,400 ÷ 24 = 100
Calculate for 6 hours: 100 x 6 = 600

7,200 + 600 = 7,800 watt-hours
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What quadrilateral always has 4 congruent angles and opposite that are congruent and paralle
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Another quadrilateral that you might see is called a rhombus. All four sides of a rhombus are congruent. Its properties include that each pair of opposite sides is parallel, also making it a parallelogram. In summary, all squares are rectangles, but not all rectangles are squares.
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Answer:

11+x because the equation is reversabel.

Step-by-step explanation:

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