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goldenfox [79]
4 years ago
9

PLEபாப்Nச*பபபபபபபபப-பாாபோபாபாபாஇப்பகன்​

Mathematics
2 answers:
WINSTONCH [101]4 years ago
6 0
No the answer is
N = *・゜゚・*:.。..。.:*・'(*゚▽゚*)'・*:.。. .。.:*・゜゚・*
r-ruslan [8.4K]4 years ago
5 0

the answer is

போபாபாபா = Popapapa

i think....

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Find the x and y-intercepts of the following:
svet-max [94.6K]

Answer:

x-intercept (-3,0); y-intercept (0,12)

Step-by-step explanation:

To find the x-intercept --> y should equal 0

8x-2(0)=-24 substitute

8x=-24 divide

x=-3 (-3,0)

To find they-intercept --> x should equal 0

8(0)-2y=-24 substitute

-2y=-24 divide

y=12 (0,12)

5 0
3 years ago
What is the equation of the midline for the function f(x) ?<br> f(x)=3cos(x)−2.5
fredd [130]
Y= -2.5
the midline is basically the line where the distance is the same to the line from the max and the min 
7 0
3 years ago
Read 2 more answers
A car moves at a constant speed of 90km/h from a starting point. Another car moves at 70km/h after 2hours from the same starting
patriot [66]

Step-by-step explanation:

are you sure you wrote the problem here correctly ?

because the distance will be 40km after less than half an hour just by the first car driving. way before the second car even starts.

to be precise, it would be after 60 minutes × 40 / 90

(= how many minutes of an hour are needed to reach 40km while going 90km/h) :

60 × 40 / 90 = 60 × 4 / 9 = 20 × 4 / 3 = 80/3 = 26.67 minutes.

but maybe the question was about 400km distance between the two cars.

so, the first car goes 90km/h for 2 hours.

at that moment it will be 2×90=180km ahead.

that would mean that 220km are still missing for the 400km assumption.

with each hour driving the first car makes 20km more than the second car.

to build up 220km that way would require

220/20 = 11 hours.

plus the 2 original head start hours this would make 13 hours as overall answer.

7 0
3 years ago
The blades of a windmill turn on an axis that is 40 feet from the ground. The blades are 15 feet long and complete 3 rotations e
astraxan [27]

Answer:

a is the _amplitude_(Length of the blades)_

The vertical shift, k, is the _Mill shaft height_

a = 15\ ft\\\\k = 40\ ft

y = 15sin(\frac{\pi}{10}t) + 40

Step-by-step explanation:

In this problem the amplitude of the sinusoidal function is given by the length of the blades.

a = 15\ ft

The mill is 40 feet above the ground, therefore the function must be displaced 40 units up on the y axis. So:

k = 40\ ft

We know that the blades have an angular velocity w = 3 rotations per minute.

One rotation = 2\pi

1 minute = 60 sec.

So:

w = \frac{3(2\pi)}{60}\ rad/s

w = \frac{\pi}{10}\ rad/s

Finally:

a is the _amplitude_(Length of the blades)_

The vertical shift, k, is the _Mill shaft height_

a = 15\ ft\\\\k = 40\ ft

y = 15sin(\frac{\pi}{10}t) + 40

3 0
4 years ago
Read 2 more answers
What is nine minus one third?
Katarina [22]

Answer:

\frac{26}{3}=8.6...=8\frac{2}{3}

Step-by-step explanation:

You multiply 9 x 3=27

(leave 1/3 alone, it's already good)

you have a 27/3-1/3

(subtract those)

your answer is 26/3

(see answer above for decimal form and mixed fraction form)

8 0
2 years ago
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