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Leto [7]
3 years ago
10

2. 64 oz = ? lb A. 2 lb B. 4 lb C. 8 lb D. 128 lb

Mathematics
2 answers:
Nutka1998 [239]3 years ago
6 0

Answer: b) 4lb

Step-by-step explanation:

lara [203]3 years ago
5 0

Answer:Your answer is B

Step-by-step explanation:

64 oz is= to 4 lb

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12a - 6 + 7a - 2a ; a = 4<br> Need help please
Novosadov [1.4K]

Answer:

62

Step-by-step explanation:

Plug in the value of a in the equation:

12(4) - 6 + 7(4) - 2(4)

Solve 12(4) - 6:

12(4) - 6 = 48 - 6 = 42

Solve 7(4) - 2(4):

7(4) - 2(4) = 28 - 8 = 20

Combine both answers (42+20):

42+20 = 62

Complete answer:

12(4) - 6 + 7(4) - 2(4) = 62

3 0
3 years ago
Is 5(b+3) equivalent to 3(b+5)?​
Viktor [21]

Answer:

No, because using the distributive property, you would get 5b+15  and 3b+15. The number of b you have is different.

5 0
3 years ago
Read 2 more answers
Question 6 (4 points)
Kay [80]

Answer:

I believe it would be answer 2)

Step-by-step explanation:

The team has 4 players and the line graph starts at 5 increasing to 9

3 0
3 years ago
Read 2 more answers
If Upper X overbar equals 62​, Upper S equals 8​, and n equals 36​, and assuming that the population is normally​ distributed, c
marishachu [46]

Answer:

The 99% confidence interval would be given by (58.373;65.627)    

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=62 represent the sample mean

\mu population mean (variable of interest)

s=8 represent the sample standard deviation

n=36 represent the sample size  

Part a: Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=36-1=35

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,35)".And we see that t_{\alpha/2}=2.72

Now we have everything in order to replace into formula (1):

62-2.72\frac{8}{\sqrt{36}}=58.373    

62+2.72\frac{8}{\sqrt{36}}=65.627    

So on this case the 99% confidence interval would be given by (58.373;65.627)    

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

3 0
3 years ago
The heart rate of 10 football players is sampled. The rates measured in beats per minute are 62,74,74,64,76,6480,76,68,76
Alona [7]

Answer:

71.4

Step-by-step explanation:

The Test

7 0
3 years ago
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