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ArbitrLikvidat [17]
3 years ago
6

15+10•8 div by 4 must equal 35

Mathematics
2 answers:
8090 [49]3 years ago
8 0
(15+10= 25)  times 8 is 200. 200 divided by 4 is 50. So no , therefore it isnt 35. Its 50.
Paraphin [41]3 years ago
3 0
15+10•8
25•8 = 200
Then 200 divided by 4 would equal 50 it does NOT equal 35
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Determine the y-intercept of 5x-6y=10
Tema [17]

Answer:

The y intercept of the equation is 10.

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3 years ago
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Please help me!!!! Thank you
serg [7]

\huge  \rm༆ Answer ༄

In the given question, the two sides of the given triangles are parallel, so the the two corresponding angles of the Triangles are equal to one another.

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And since they are similar, the ratio of sides of one Triangle will be equal to ratio of corresponding sides of the other Triangle.

that is ~

  • \sf \dfrac{5}{7}  =  \dfrac{5 + 6}{y}

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  • \sf y =  \dfrac{77}{5}

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3 years ago
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SashulF [63]
m<1=123

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3 0
3 years ago
Solve the system of equation <br> Y=4x-11<br> Y=x+13<br><br> X=<br><br><br> Y =
Phoenix [80]

Answer:

(8,21)

Step-by-step explanation:

Since both equations equal y, set both equaitions equal to each other

and solve for x

4x-11=x+13 , subtract x from both sides

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3x=24, divide both sides by 3 to get x alone

x=8

Substitute x=8 into either equation to solve for y

y=4(8)-11

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5 0
4 years ago
What is the solution of x^2+x-6/x-7&lt;0 PLEASE HELP ME :( (it’s not the 2nd one i already tried it)
blsea [12.9K]

Answer:

the first one  \:x\le \:-3\quad \mathrm{or}\quad \:2\le \:x

Step-by-step explanation:

Factor x^2+x-6 :

Break the expression into groups

\left(x^2-2x\right)+\left(3x-6\right)

\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2-2x\mathrm{:\quad}

x\left(x-2\right)

\mathrm{Factor\:out\:}3\mathrm{\:from\:}3x-6\mathrm{:\quad}

3\left(x-2\right)

x\left(x-2\right)+3\left(x-2\right)

\mathrm{Factor\:out\:common\:term\:}x-2

\left(x-2\right)\left(x+3\right)

\frac{\left(x-2\right)\left(x+3\right)}{x-7}\\

\frac{\left(x-2\right)\left(x+3\right)}{x-7}\le \:0

\mathrm{Find\:the\:signs\:of\:the\:factors\:of\:}\frac{\left(x-2\right)\left(x+3\right)}{x-7}

\mathrm{Identify\:the\:intervals\:that\:satisfy\:the\:required\:condition:}\:\le \:\:0

x

Merge Overlapping Intervals

x\le \:-3\quad \mathrm{or}\quad \:2\le \:x

6 0
3 years ago
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