Answer:
Were my money?
Step-by-step explanation:
May I have brainliest please I'm trying to level up!
</3 PureBeauty
Answer:
3.6
Step-by-step explanation:
The computation of the equations is illustrated below.
<h3>How to illustrate the equation?</h3>
a. x - y = 1 .... i
x + y = -9 ..... ii
Subtract the equations
-2y = 10
y = 10/-2 = -5
Since x - y = 1
x - (-5) = 1
x + 5 = 1
x = 1 - 5 = -4
b. 3x + 2y = -9
x - y = -13
Multiply equation i by 1
Multiply equation ii by 3
3x + 2y = -9
- 3x - 3y = -39
5y = 30
y = 6
Since x - y = 13
x - 6 = 13
x = 13 + 6 = 19
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Answer:
a^3 - b^3.
Step-by-step explanation:
Area = length * breadth
= (a - b)(a^2 + ab + b^2)
= a(a^2 + ab + b^2) - b(a^2 + ab + b^2)
= a^3 + a^2b + ab^2 - a^2b - ab^2 - b^3
Note: the 4 middle terms cancel out. So the answer is
a^3 - b^3.
<u>Annotation</u>General formula for distance-time-velocity relationship is as following
d = v × t
The velocity of the first car will be v₁, the time is 2 hours, the distance will be d₁.
The velocity of the second car will be v₂, the time is 2 hours, the distance will be d₂.
One of them traveling 5 miles per hour faster than the others. That means the velocity of the first car is 5 miles per hour more than the velocity of the second car.
v₁ = v₂ + 5 (first equation)
The distance of the two cars after two hours will be 262 miles apart. Because they go to opposite direction, we could write it as below.
d₁ + d₂ = 262 (second equation)
Plug the d-v-t relationship to the second equationd₁ + d₂ = 262
v₁ × t + v₂ × t = 262
v₁ × 2 + v₂ × 2 = 262
2v₁ + 2v₂ = 262
Plug the v₁ as (v₂+5) from the first equation2v₁ + 2v₂ = 262
2(v₂ + 5) + 2v₂ = 262
2v₂ + 10 + 2v₂ = 262
4v₂ + 10 = 262
4v₂ = 252
v₂ = 252/4
v₂ = 63
The second car is 63 mph fast.Find the velocity of the first car, use the first equationv₁ = v₂ + 5
v₁ = 63 + 5
v₁ = 68
The first car is 68 mph fast.
Answer