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3 years ago

12

Right 720,080 in expanded form and in exponents

1 answer:

Xelga [282]3 years ago

7 0

Expanded form: 720,080 = 700,000 + 20,000 + 80

To write in exponential form, it's easier to write it out.
700,000 + 20,000 + 80.
7<u>00</u>,<u>000</u> = 7 x 10^<u>5</u> (the exponent equals how many zeros there are.)
20,000 = 2 x 10^4 (There are 4 zeros so the exponent is 4)
80 = 8 x 10^1 (There are 1 zero so the exponent is 1)

Exponential form: (7 x 10^5) + (2 x 10^4) + (8 x 10^1)

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3/8 - 10/13<br><br> -7/5<br> -30/104<br> -41/104<br> -39/80

salantis [7]

Answer:

-41/104

Step-by-step explanation:

Simplify 3/8 and 10/13 then calculate the least common multiple, calculate multipliers, make equivalent fractions and Add fractions that have a common denominator for your final answer.

4 0

4 years ago

Consider the differential equation,

kondor19780726 [428]

Answer:

The two solutions are given as $y_1(t)=\dfrac{1}{9}e^{-8t}+\dfrac{8}{9}e^{t}$ and $y_2(t)=\dfrac{-1}{9}e^{-8t}+\dfrac{1}{9}e^{t}$

Step-by-step explanation:

As the given equation is

$y''+7y'-8y=0\\$

So the corresponding equation is given as

$m^2+7m-8=0$

Solving this equation yields the value of m as

$(m+8)(m-1)=0\\m=-8, m=1$

Now the equation is given as

$y(t)=C_1e^{m_1t}+C_2e^{m_2t}$

Here m1=-8, m2=1 so

$y(t)=C_1e^{-8t}+C_2e^{t}$

The derivative is given as

$y'(t)=-8C_1e^{-8t}+C_2e^{t}$

Now for the first case y(t=0)=1, y'(t=0)=0

$y(t=0)=C_1e^{-8*0}+C_2e^{0}\\1=C_1+C_2\\\\y'(t=0)=-8C_1e^{-8*0}+C_2e^{0}\\0=-8C_1+C_2$

So the two equation of co-efficient are given as

$C_1+C_2=1\\-8C_1+C_2=0$

Solving the equation yield

$C_1=1/9 \\C_2=8/9$

So the function is given as

$y_1(t)=\dfrac{1}{9}e^{-8t}+\dfrac{8}{9}e^{t}$

Now for the second case y(t=0)=0, y'(t=0)=1

$y(t=0)=C_1e^{-8*0}+C_2e^{0}\\0=C_1+C_2\\\\y'(t=0)=-8C_1e^{-8*0}+C_2e^{0}\\1=-8C_1+C_2$

So the two equation of co-efficient are given as

$C_1+C_2=0\\-8C_1+C_2=1$

Solving the equation yield

$C_1=-1/9 \\C_2=1/9$

So the function is given as

$y_2(t)=\dfrac{-1}{9}e^{-8t}+\dfrac{1}{9}e^{t}$

So the two solutions are given as $y_1(t)=\dfrac{1}{9}e^{-8t}+\dfrac{8}{9}e^{t}$ and $y_2(t)=\dfrac{-1}{9}e^{-8t}+\dfrac{1}{9}e^{t}$

7 0

3 years ago

Which system of equations has the same solution as the system below?

scoundrel [369]

I did this on photomath and it said -66

3 0

3 years ago

Find the x component of the vector 92.5 m 32.0 degrees

Marrrta [24]

2960m It should be correct

5 0

3 years ago

Read 2 more answers

Henry says that his set of numbers includes all integers. Iliana argues that he is wrong.

Oduvanchick [21]

Answer:

Iliana is correct because Henry included a fraction. Fractions are not integers.

8 0

3 years ago