100ml u see 20% of 100 is 20 20% of 1000 is 200 so divide 200/2 =100
Line joining (-3, -1) and (1/2, 2)
Point point form for a line is
(c-a)(y-b) = (d-b)(x-a)
(1/2 - - 3)(y - -1) = (2 - -1)(x - -3)
(7/2)(y+1)=3(x+3)
7(y+1)=6(x+3)
7 - 6(3) = 6x - 7y
6x - 7y = -11
Answer: second choice, 6x - 7y = -11
The cows of Argentina needs an approximate area of 4200 m² for grazing, and there is a total of 4500 cows.
And we are asked to find the total area of their grazing but in hectares. So, we can write:
Then, for 4500 cows:
We know that, 1 hectares = 10000 m² = 10⁴ m²
Then let the area of the field be x in hectares:
Then, putting them in proportion, We will get:
So, the total area in hectares = <u>1</u><u>8</u><u>9</u><u>0</u><u> </u><u>hectares</u><u>.</u>
And we are done !!
#CarryOnLearning
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Current amount in account
P=36948.61
Future value of this amount after n years at i=11% annual interest
F1=P(1+i)^n
=36948.61(1.11)^n
Future value of $3000 annual deposits after n years at i=11%
F2=A((1+i)^n-1)/i
=3000(1.11^n-1)/0.11
We'd like to have F1+F2=280000, so forming following equation:
F1+F2=280000
=>
36948.61(1.11)^n+3000(1.11^n-1)/0.11=280000
We can solve this by trial and error.
The rule of 72 tells us that money at 11% deposited will double in 72/11=6.5 years, approximately.
The initial amount of 36948.61 will become 4 times as much in 13 years, equal to approximately 147800 by then.
Meanwhile the 3000 a year for 13 years has a total of 39000. It will only grow about half as fast, namely doubling in about 13 years, or worth 78000.
Future value at 13 years = 147800+78000=225800.
That will take approximately 2 more years, or 225800*1.11^2=278000.
So our first guess is 15 years, and calculate the target amount
=36948.61(1.11)^15+3000(1.11^15-1)/0.11
=280000.01, right on.
So it takes 15.00 years to reach the goal of 280000 years.
Sqaure
rhombus
parallelogram
quadrilateral
hope it helps
