Question

What are the zeros of the quadratic function f(x) equals 6X squared +12 X -7

Answer 1

The zeroes of the function will be $\rm -1 \pm \dfrac{\sqrt{78}}{6}}$

What is a Quadratic Function ?

A quadratic function is given by ax² +bx+c = f(x)

The given quadratic function is

f(x) = 6x² +12x - 7

The zeroes of the function will be given by

f(0) = 0

6x² +12x - 7 = 0

The zeroes are given by

$\rm \dfrac {-b \pm \sqrt{b^2 -4ac}}{2a}$

here

a = 6

b = 12

c = -7

Therefore the zeroes of the function will be

$\rm \dfrac {-12 \pm \sqrt{12^2 -4*6*(-7)}}{2 *6}$

$\rm \dfrac {-12 \pm \sqrt{312}}{12}$

$\rm -1 \pm \dfrac{\sqrt{78}}{6}}$

Therefore these are the two zeroes of the function.

To know more about Quadratic Function

brainly.com/question/27918223

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