You must drive more than 40 miles to make option A the cheaper plan
<em><u>Solution:</u></em>
Two payment options to rent a car
Let "x" be the number of miles driven in one day
<em><u>You can pay $20 a day plus 25¢ a mile (Option A)</u></em>
25 cents is equal to 0.25 dollars
OPTION A : 20 + 0.25x
<em><u>You pay $10 a day plus 50¢ a mile (Option B)</u></em>
50 cents equal to 0.50 dollars
Option B: 10 + 0.50x
<em><u>For what amount of daily miles will option A be the cheaper plan ?</u></em>
For option A to be cheaper, Option A must be less than option B
Option A < Option B
Solve the inequality
Add -0.50x on both sides
Add - 20 on both sides,
Divide both sides by 0.25
Thus you must drive more than 40 miles to make option A the cheaper plan
Answer:
1) (2,4)
2) (5,-2)
Step-by-step explanation:
those are the points at which the lines cross making them the solutions to the equations
Answer:
$7,185 see below ↓
explanation:
With median, it is about the number that appears the most, and since the closest it gets is between $7,071 and $7,195, we have to pick the number that averages in-between which in this case is <em>7,185.</em>
Below, this ↓ array proves the logic.
<em />
Answer:
c is answer.....................
9514 1404 393
Answer:
60
Step-by-step explanation:
The minimum number required is the least common multiple (LCM) of 15 and 4. The numbers 15 and 4 have no common factors, so their LCM is their product.
15×4 = 60 strands are required