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Answer: $225,000
Explanation:
Given that,
Company acquired a mine = $970,000 of this amount,
Land value = $100,000 and remaining portion to the minerals in the mine
Ore appear to be in the mine = 12,000,000 units
Aristotle incurred development costs = $170,000
fair value of its obligation = $40,000
ore were extracted = 2,500,000 units
Units sold = 2,100,000
=
= $0.09 depletion per unit
The total amount of depletion for 2017 = depletion per unit × ore were extracted
= $0.09 × 2,500,000
= $225,000
Answer:
The Linear programming model is given as below
Profit Function:
Constraints:
Explanation:
As the question is not complete, the complete question is found online and is attached herewith.
Let the number of product 1 to be produced is X, that of product 2 is Y and product 3 is Z
so the maximizing function is the profit function which is given as
Now as the number of hours in a week are 40 and there are a total of 10 type 1 machines so the total number of machine 1 hours are 40*10=400 hours
As from the given table product 1 uses 2 machine hours of machine 1, product 2 uses 2 machine hours of machine 1 and product 3 uses 1 hour of machine 1 so
Now as the number of hours in a week are 40 and there are a total of 6 type 2 machines so the total number of machine 2 hours are 40*6=240 hours
As from the given table product 1 uses 3 machine hours of machine 2, product 2 uses 4 machine hours of machine 2 and product 3 uses 6 hour of machine 2 so
Now as the number of hours in a week are 40 and there are a total of 8 type 3 machines so the total number of machine 3 hours are 40*8=320 hours
As from the given table product 1 uses 4 machine hours of machine 3, product 2 uses 6 machine hours of machine 3 and product 3 uses 5 hour of machine 3 so
Now as the machine 1 is used as 2X+2Y+Z in a week and the week is of 40 hours so the number of machines to be used are given as
Now as the machine 2 is used as 3X+4Y+6Z in a week and the week is of 40 hours so the number of machines to be used are given as
Now as the machine 3 is used as 4X+6Y+5Z in a week and the week is of 40 hours so the number of machines to be used are given as
Now the workers are available for 35 hours so the worker available at the machine 1 is given as
That of machine 2 is given as
That of machine 3 is given as
As the total number of workers is 19 so the constraint is given as
So the Linear programming model is given as below
Profit Function:
Constraints:
