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2 years ago

5

2. What are some examples of numbers that are not rational?

1 answer:

8_murik_8 [283]2 years ago

7 0

Answer:

π (Pi) is a famous irrational number.

Step-by-step explanation:

https://www.google.com/url?sa=i&source=images&cd=&ved=2ahUKEwiOs5uTkYHnAhUHVK0KHQG8D_gQjRx6BAgBEAQ&url=https%3A%2F%2Fwww.mathwarehouse.com%2Farithmetic%2Fnumbers%2Frational-and-irrational-numbers-with-examples.php&psig=AOvVaw1ZOfWq7B8H6G4s5Qp78RI-&ust=1579024048084516

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I need help on my homework... plz

Kazeer [188]

Nevermind i see it. one sec

7 0

3 years ago

1.The growth of a sample of bacteria can be modeled by the function b(t)=100(1.06)t where b is the number of bacteria and t is t

qwelly [4]

Given:

The growth of a sample of bacteria can be modeled by the function

$b(t)=100(1.06)^t$

where, b is the number of bacteria and t is time in hours.

To find:

The number of total bacteria after 3 hours.

Solution:

We have,

$b(t)=100(1.06)^t$

Here, b(t) number of total bacteria after t hours.

Substitute t=3 in the given function, to find the number of total bacteria after 3 hours.

$b(t)=100(1.06)^3$

$b(t)=100(1.191016)$

$b(t)=119.1016
$

Therefore, the number of total bacteria after 3 hours is 119.1016.

4 0

2 years ago

You are having a wedding anniversary party. In attendance are a grandfather, a grandmother, two fathers, two mothers, four child

Zepler [3.9K]

After counting, there are 23 people in attendance. If each person is eating two burgers:

$23*2=46$

You'll need at least 46 burgers.

8 0

2 years ago

If 18.9 million computers were in use in 1980 and the number is rising by 19% annually, predict the number of computers in use i

4vir4ik [10]

18.9(1+0.19)^35, 35 is the number of years
use your calculator, you should get 661.5, round to the newest whole number 662million

4 0

2 years ago

Principal = 5300=5300 rupees

PSYCHO15rus [73]

Answer:

Using the formula:

$A=P+I$

where

A is the total amount

P is the principal

I is the Simple Interest

As per the statement:

Principal(P) = 5300 rupees.

rate of interest(r) = 6.5% = 0.065

Total amount(A) = 6678 rupees.

Then using above formula we have;

$6678 = 5300+I$

Subtract 5300 both sides we get;

$1378 = I$

or

$I = \$1378$

We have to find the time period.

Using formula of Simple interest:

$I = Prt$

where r is the rate of interest (in decimal)

here, r = 6.5% = 0.065

Substitute the given values top find t:

$1378 = 5300 \cdot 0.065 \cdot t$

⇒ $1378 = 344.5t$

Divide both sides by 344.5 we have;

$4 = t$

Therefore, the time period t in years is 4 years

8 0

3 years ago