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yulyashka [42]
3 years ago
12

Rewrite as a simplified fraction.

Mathematics
1 answer:
Alex17521 [72]3 years ago
3 0
1157/500 is as simple it can be as a fraction .
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What expression shows the relationship between the value of any term and n, its position in the sequence for the given sequence?
san4es73 [151]

Answer:

a(n)=3+(n-1)2

Step-by-step explanation:

a(n)=3+(n-1)2

arithmetic sequence

5 0
3 years ago
Can someone help me please!!
Kisachek [45]

9514 1404 393

Answer:

  AE = CE = 23; BE = DE = 20

Step-by-step explanation:

Put the values of the variables in their place and do the arithmetic.

  AE = 2u+5 = 2(9) +5 = 23

  BE = 6v-1 = 6(3.5) -1 = 20

  CE = 3u-4 = 3(9) -4 = 23

  DE = 8v-8 = 8(3.5) -8 = 20

The diagonals cross at their midpoints, so the quadrilateral is a parallelogram.

6 0
2 years ago
Find the sine of angle S. Reduce the answer to the lowest terms.
NeX [460]

Answer:

\sin e\text{ S = }\frac{3}{5}

Explanation:

Here, we want to get the value of sine S

The sine of an angle is the ratio of the opposite side to the hypotenuse side

The hypotenuse side is the side that faces the right angle which is the small box. It is the longest side of the triangle and it measures 10

The opposite is the side that faces the angle which is 6

We have the sine as:

\frac{6}{10}\text{ = }\frac{3}{5}

8 0
1 year ago
Which equation is equivalent to 2x+4a=10 A. X= 5/4a B.5+2a C. X=10-4a D. X=5-2a
kifflom [539]
Alright, so we start off my subtracting 4a from both sides, separating the x and getting 10-4a=2x. Next, we divide both sides by 2, getting that 5-2a=X
5 0
3 years ago
Read 2 more answers
15 pigs are entered in the best pet competition at the county fair. The judges will award very special pigs with blue, red, and
Yuki888 [10]
At the beginning, there are 15 pigs without ribbons. one of the pigs receives a ribbon. how many are left ribbonless? 
<span>14. when another pig is given a ribbon, there are 13 left. after all the ribbons have been given out, 3 of the 15 pigs have ribbons. </span>
<span>if any one of the 15 at the beginning is given a ribbon, there are 15 possible combos. for the second ribbon, there are 14 combos- but each of those combos has to go through the first 15. for the third ribbon, there are 13 combos, going through 14 and 15. </span>
<span>simply put, 15 x 14 x 13.</span>
6 0
3 years ago
Read 2 more answers
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