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3 years ago

How do you determine the square root of a term whose variable(s have exponents greater than 2?

Mathematics

1 answer:

4vir4ik [10]3 years ago

7 0

Basic method is Synthetic Division and Factor Theorem

Step-by-step explanation:

For higher-degree equations, the question becomes more complicated than others: cubic and quadratic equations can be solved by similar formulas.

Hence, to avoid those circumstances we can use Synthetic Division and Factor theorem to determine the squares of the given polynomial those who have order higher than 2.

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Mr. Whittaker’s science class uses tide gauges to measure annual variations in water levels at different parts of a river, and t

strojnjashka [21]

Answer:

-1.05 mm/year

2.48 years

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The entire graph of the function f is shown in the figure below.

postnew [5]

Answer:

below

Step-by-step explanation:

domain. = ( -5 , 4)

range = ( -2 , 3)

6 0

3 years ago

The smiths have two children. The sum of their ages is 23. The produce of their ages is 132. How old are the children?

kolezko [41]

For this case we propose a system of equations:

x: Let the variable representing the age of the first child of the Smiths

y: Let the variable representing the age of the second child of the Smiths

According to the data of the statement we have to:

$x + y = 23\\x * y = 132$

From the first equation we have to:

$x = 23-y$

We substitute in the second equation:

$(23-y) * y = 132\\23y-y ^ 2 = 132\\y ^ 2-23y + 132 = 0$

We find the solutions by factoring:

We look for two numbers that, when multiplied, result in 132 and when added, result in 23. These numbers are 11 and 12.

Thus, we have that the factorized equation is:

$(y-11) (y-12) = 0$

Thus, the solutions are: $y_ {1} = 11\\y_ {2} = 12$

So, we can take any of the solutions:

With $y = 11$

Then $x = 23-11 = 12$

Therefore, the ages of the children are 11 and 12 respectively.

Answer:

The ages of the children are 11 and 12 respectively.

6 0

3 years ago

for events A and B, P(A)= 3/14 and P(B)= 1/5. Also, P(A and B)= 3/65. Are A and B independent events?

Lady_Fox [76]

No, A and B are not independent events

Step-by-step explanation:

Let us study the meaning independent probability

Two events are independent if the result of the second event is not affected by the result of the first event
If A and B are independent events, the probability of both events is the product of the probabilities of the both events P (A and B) = P(A) · P(B)

∵ P(A) = $\frac{3}{14}$